So hmmm x²+6x+8=0
alrite.. let's do some grouping now
( x² + 6x + [?]²) + 8 = 0
notice above, we have a missing fellow in order to get a perfect square trinomial... hmm who would that be?
let's take a peek at the middle guy of the trinomial.. 6x.. hmmm let's factor it, 2*3*x, wait a minute! 2 * 3 * x... we already have x² on the left-side, since the middle term is just 2 * the square root of the other two terms, that means that the guy on the right, our missing guy must be "3"
alrite, let's add 3² then, however, bear in mind that, all we're doing is borrowing from our very good friend Mr Zero, 0
so if we add 3², we also have to subtract 3², let's do so
(x² + 6x +3² - 3²) + 8 = 0
(x² + 6x +3²) + 8 - 3² = 0
(x+3)²=3² - 8
(x+3)² = 1
You need to upload the image if you want the answer.
However, I can explain how to solve the problem so that you can determine the angle.
cos theta = side opposite of theta divided by the hypotenuse.
Reminder that the hypotenuse is the side NOT touching the 90° angle.
Hope this helps! If not, upload an image of the drawing.
Answer:


Step-by-step explanation:
<u>Trigonometric Formulas</u>
To solve this problem, we must recall some basic relations and concepts.
The main trigonometric identity relates the sine to the cosine:

The tangent can be found by

The cosine and the secant are related by

They both have the same sign.
The sine is positive in the first and second quadrants, the cosine is positive in the first and fourth quadrants.
The sine is negative in the third and fourth quadrants, the cosine is negative in the second and third quadrants.
We are given

Find the cosine by solving





We have placed the negative sign because we know the secant ('sex') is negative and they both have the same sign.
Now compute the tangent

Rationalizing


<h3>The solutions are:</h3>

<em><u>Solution:</u></em>
<em><u>Given that,</u></em>

From eqn 2,
3x - y = 1
y = 3x - 1
<em><u>Substitute the above in eqn 1</u></em>

<h3>When, x = 0 </h3>
Substitute x = 0 in eqn 2
3(0) - y = 1
y = -1
<h3>When x = 1/3</h3>
Substitute x = 1/3 in eqn 2

Thus solutions are:
