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drek231 [11]
3 years ago
9

Write an equation of the line that passes through the origin and

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

Answer:y = 3x

Step-by-step explanation:

Vanyuwa [196]3 years ago
6 0

Answer:

y = 3x

Step-by-step explanation:

Parallel lines have the same slope, so the slope of this new line will be the same as the given one.

For a line to pass through the origin it needs to have a y intercept of 0, because the origin is the point (0,0).

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Please I have the answers I just want to double check them and Solve key: B=42  A=93  N=29  X=36 1. (b-7)(2b-7) 2. (4a-4)(5a-7)
Nady [450]
1. <span>(b-7)(2b-7) = 2</span>b^{2} -21b +49; b = 42 => 2*41^{2} -21*42 + 49 =
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3 years ago
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Find the slope of line that passes through (5,6) and (7,9)
Debora [2.8K]

Answer: \frac{3}{2}

Step-by-step explanation:

m=\frac{9-6}{7-5}

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3 years ago
a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure
dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

y=-0.01x^2+0.5x+3

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

8=-0.01x^2+0.5x+3

8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100

800=-x^2+50x+300

-x^2+50x-500=0

x^2-50x+500=0

we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}

x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)

x=13.82,x=36.2

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

y=-0.01(30)^2+0.5(30)+3

y=9ft

we know that

height of net is 8 ft

so, the ball will go over the net


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