Answer: They would die, or go insane
Explanation: First off, they need to have a steady food supply to maintain society. If, lets say, the food ran out, then everyone would die as they were isolated and had no other food source. Since the human body needs to have interaction, if a certain group of people were isolated, they would most likely also go insane due to the lack of no other people. Of course, the info you gave was very vague, so I couldn't really give a good answer, so yeah
Hi there!
It forms fecal waste. Fecal waste is made of whatever’s left after the large intestine absorbs the needed nutrients and minerals.
Hope this answers your question!
Answer:
Detail is given below.
Explanation:
Given data:
Mass of enzyme = 32 g
Volume of water = 42.50 mL
Volume of water+ enzyme = 48.0 mL
Density of enzyme = ?
Solution:
Density is equal to the mass divided by volume.
First of all we will calculate the volume of enzyme.
Volume of enzyme = (volume of water+ enzyme ) - Volume of water
Volume of enzyme = 48.0 mL - 42.50 mL
Volume of enzyme = 5.5 mL
Density of enzyme:
d = 32 g/ 5.5 mL
d = 5.8 g/mL
2)
Given data:
Mass of cup = 14 g
Volume of cup = ?
Density of cup = 2 g/cm³
Solution:
Density is equal to the mass divided by volume.
Formula:
d = m/v
2 g/cm³ = 14 g/ v
v = 14 g/2 g/cm³
v = 7 cm³
3) What are the four ways to measure matter?
weight, mass, volume, density
4) Given data:
Mass of rock = 18.5 g
volume of rock = 3cm³
density of rock = ?
Solution:
Formula:
d = m/v
d = 18.5 g/ 3cm³
v = 6.16 g/cm³
5)
Given data:
mass = 6g
density = 8 g/cm³
missing value = ?
Solution:
d = m/v
8 g/cm³ = 6g / v
v = 6g/8 g/cm³
v = 0.75cm³
6)
Given data:
Volume of liquid in cylinder = 48 mL
Volume of toy car and liquid = 52 mL
Volume of car = ?
Solution:
Volume of car = volume of of toy car and liquid - Volume of liquid in cylinder
Now we will put the values.
Volume of car = 52 mL - 48 mL
Volume of car = 4 mL
If a lot of tryptophan is present, the operon will be repressed.
Under intermediate amounts of tryptophan, the change to stop codons would cause the ribosome to stall and therefore would mimic as if there were no tryptophan present.
If no tryptophan present, the operon would be maximally expressed.
a - True. The ribosome would always be stalled in the leader sequence - so this wouldn't matter. However, the operon would still be transcribed because the repressor would be active (remember Trp operon is controlled both by attenuation and repression). True as long as there's not much tryptophan to activate the repressor!
b- True - With no tryptophan the repressor isn't engaged and the ribosome is stalled in the leader sequence.
c- Matters about how much tryptophan is available. So True if there's lots of tryptophan available.
d- I would choose this one as all of the above could be true depending on the levels of tryptophan.
