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GuDViN [60]
3 years ago
13

I need help with this​

Mathematics
1 answer:
Inessa [10]3 years ago
8 0

Step-by-step explanation:

2x = 4x - 6, => x = 3.

3x = y, => y = 9.

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2 years ago
Solve <br>|-4b-8|+|-1-b^2|+2b^3. b= -2<br>show steps please .
evablogger [386]
Ok, first put in the -2 for each b. That gives:
|-4(-2)-8|+|-1(-(-2))^2|+2(-2)^3
Let's do each section.
The first section is |-4(-2)-8)|
-4 times -2 is 8, minus 8 is 0. The absolute value of 0 is still 0.
Now we move on to |-1(-(-2))^2)|
First we do exponents
-(-2) is 2, and 2^2 is 4. 4 times -1 is -4. The absolute value of -4 is 4
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-8*2=-16.
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