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Lina20 [59]
3 years ago
7

Lukas plotted these points on the number line. Point A: −12 3 Point B: −2 3 Point C: −11 3 Point D: −22 3 Which point did he plo

t incorrectly? Point
Mathematics
2 answers:
kherson [118]3 years ago
8 0

Answer:

Point A

Step-by-step explanation:

chubhunter [2.5K]3 years ago
6 0

Answer:

The answer is A.

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What is the largest amount - 2 pt 4 fl oz., 5 cups or 39 fl oz?
Nadusha1986 [10]
5 cups
Because
It has
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4 0
3 years ago
Please help me with 10 and 11
garik1379 [7]
10. 
( 3 x 3 x 3 ) (3) (5) = 405

and i can't read 11 sorry ):
5 0
3 years ago
Simplify 4(3x^2y^4)3 / (2x^3y^5) ^4. Show your work. (Will give 50 Points & Brainliest to correct answer.)
Delicious77 [7]

Answer:

4(3x2y4)3/(2x3y5)4

Final result :

   27

 —————

 4x6y8

Step by step solution :

Step  1  :

Equation at the end of step  1  :

   (((3•(x2))•(y4))3)

 4•——————————————————

     ((2x3•(y5))4)  

Step  2  :

Equation at the end of step  2  :

     ((3x2 • (y4))3)

 4 • ———————————————

        24x12y20    

Step  3  :

            33x6y12

Simplify   ————————

           24x12y20

Dividing exponential expressions :

3.1    x6 divided by x12 = x(6 - 12) = x(-6) = 1/x6

Dividing exponential expressions :

3.2    y12 divided by y20 = y(12 - 20) = y(-8) = 1/y8

Equation at the end of step  3  :

       27  

 4 • ——————

     16x6y8

Step  4  :

Final result :

   27

 —————

 4x6y8

7 0
4 years ago
How do I solve this using the substitution method for finding anti derivatives?
rewona [7]
A bit blurry, but if I'm making it out correctly, that's

\displaystyle\int t\sqrt{(t^2-9)^3}\,\mathrm dt=\int t(t^2-9)^{3/2}\,\mathrm dt

Set u=t^2-9. Then \mathrm du=2t\,\mathrm dt, or t\,\mathrm dt=\dfrac{\mathrm du}2. The integral is then equivalent to

\displaystyle u^{3/2}\dfrac{\mathrm du}2=\frac12\int u^{3/2}\,\mathrm du
=\dfrac12\dfrac{u^{5/2}}{\frac52}+C
=\dfrac12\times\dfrac25u^{5/2}+C
=\dfrac15u^{5/2}+C
=\dfrac15(t^2-9)^{5/2}+C
6 0
3 years ago
How do you solve 9^x=3^40?
alex41 [277]

Answer:

We have 9 = 3^2;

Then, 9^x = (3^2)^x = 3^(2x);

We solve  3^(2x) = 3^40;

2x = 40;

x = 20 ÷ 2;

x = 10;

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
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