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Lina20 [59]
3 years ago
7

Lukas plotted these points on the number line. Point A: −12 3 Point B: −2 3 Point C: −11 3 Point D: −22 3 Which point did he plo

t incorrectly? Point
Mathematics
2 answers:
kherson [118]3 years ago
8 0

Answer:

Point A

Step-by-step explanation:

chubhunter [2.5K]3 years ago
6 0

Answer:

The answer is A.

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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t
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For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

m_ {1} * m_ {2} = - 1

The given line is:

5x-2y = -6\\-2y = -6-5x\\2y = 5x + 6\\y = \frac {5} {2} x + \frac {6} {2}\\y = \frac {5} {2} x + 3

So we have:

m_ {1} = \frac {5} {2}

We find m_ {2}:m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}

So, a line perpendicular to the one given is of the form:

y = - \frac {2} {5} x + b

We substitute the given point to find "b":

-4 = - \frac {2} {5} (5) + b\\-4 = -2 + b\\-4 + 2 = b\\b = -2

Finally we have:

y = - \frac {2} {5} x-2

In point-slope form we have:

y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)

ANswer:

y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)

3 0
3 years ago
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