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gladu [14]
3 years ago
9

Evaluate the function. f(x) = -4x^2+9Find f(-3)

Mathematics
2 answers:
Svetlanka [38]3 years ago
5 0

Answer:

-27

Step-by-step explanation:

  1. f(x) = -4x² + 9
  2. f(-3) = -4(-3)² + 9
  3. f(-3) = -4(9) + 9
  4. f(-3) = -36 + 9
  5. f(-3) = -27
svetlana [45]3 years ago
4 0

Answer:

f(-3)=-27

Step-by-step explanation:

So we have the function:

f(x)=-4x^2+9

And we want to find f(-3).

So, let's substitute -3 for x. Therefore:

f(-3)=-4(-3)^2+9

Square:

f(-3)=-4(9)+9

Multiply:

f(-3)=-36+9

Add:

f(-3)=-27

And we're done!

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For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
2 years ago
A triangle had two sides of lengths 10 and 14
BartSMP [9]

Answer:

Isosceles or scalene

Isosceles has 2 sides that are the same value

scalene is where none of the sides are equal

6 0
3 years ago
Read 2 more answers
A line, y = mx + b, passes through the point (10, 3) and is parallel to the line 2x+5y=12.
slava [35]

We have been given that a line y=mx+b passes through the point (10, 3) and is parallel to the line 2x+5y=12. We are asked to find the y-intercept of the line.

First of all we will rewrite our given equation in slope-intercept form as:

2x-2x+5y=12-2x

5y=-2x+12

\frac{5y}{5}=-\frac{2}{5}x+\frac{12}{5}

y=-\frac{2}{5}x+\frac{12}{5}

We know that slope of parallel lines is equal, so slope of parallel line to our given line would be -\frac{2}{5}.

Now we will use slope-intercept form of equation to find y-intercept.

y=mx+b, where,

m = Slope,

b = The y-intercept.

Let us substitute m=-\frac{2}{5} and coordinates of point (10,3) in above equation as:

3=-\frac{2}{5}(10)+b

3=-2(2)+b

3=-4+b

3+4=-4+4+b

7=b

Therefore, the y-intercept is 7 and our required equation would be y=-\frac{2}{5}x+7.

5 0
3 years ago
g Which of the following is not appropriate to use the t-confidence interval for . a. The sample is based on a simple random sam
KATRIN_1 [288]

Answer:

d. The population standard deviation is known.

Step-by-step explanation:

T-distribution or Z-distribution, which to use?

If we have the population standard deviation is known, we use the z-distribution.

Otherwise, if we only have the standard deviation for the sample, we use the t-distribution.

Which of the following is not appropriate to use the t-confidence interval for

When the population standard deviation is known, so letter d.

7 0
3 years ago
I need help on #11&amp; #8
Musya8 [376]
100 * pi = pi * r^2
Pi cancels on both sides of the equation
So... 100= r^2
= radius is 10
5 0
4 years ago
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