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Maru [420]
3 years ago
11

Two hikers are 77 miles apart and walking toward each other. They meet in 10 hours. Find the rate of each hiker if one hiker wal

ks 3.3 mph faster than the other.
The speed of the slow hiker is_____ mph, and the speed of the fast hiker is______ mph.
Mathematics
1 answer:
disa [49]3 years ago
3 0

Answer:The rate of the slower hiker is 2.2 mph and the rate of the faster hiker is 5.5 mph

Explanation:

One hiker walks 3.3 mph faster than the other.

Suppose, the speed of the slower hiker is  mph.

So, the speed of the faster hiker will be:  

Both hikers are walking toward each other and meet in 10 hours.

We know that,  

So, the distance walked by the slower hiker in 10 hours  miles and the distance walked by the faster hiker in 10 hours

miles.

Given that, they were 77 miles apart in the beginning. So the equation will be

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A=\dfrac{1}{2}ab\Rightarrow 2ab=4A\\P=a+b+c\Rightarrow a+b=P-c

Therefore:

(P-c)^2=c^2+4A\\P^2-2cP+c^2=c^2+4a\\2cP=P^2-4A\\c=\dfrac{P^2-4A}{2P}

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Answer:

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Step-by-step explanation:

Let the x be the number of hours after noon.

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Perp.:  The lines have slopes that are negative reciprocals of one another.

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