The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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9514 1404 393
Answer:
- left 3 units
- up 4 units
- shape: lower left image
Step-by-step explanation:
For a parent function f(x), the transformations ...
g(x) = a×f(x -h) +k
cause ...
- vertical expansion by 'a', reflection over x-axis if negative
- right shift by 'h'
- up shift by 'k'
Here, we have parent function f(x) = 1/x with a=-1, h=-3, k=4. Then the transformations are ...
horizontal shift left 3 units
vertical shift up 4 units
reflection over x-axis, so curves are above-left and below-right of the reference point (Note that the reflection is done <em>before</em> the translation.)
Answer:
d would be the answer
Step-by-step explanation:
i took the test
Answer:
Step-by-step explanation:
Given that reading on thermometer is N (0,1)
7% of the thermometers are rejected because they have readings that are too low, but all other thermometers are acceptable
This implies that we have to find out the 7th percentile.
i.e. Z score = -1.475
Hence the temperature for cutoff is below -1.475 degrees.
the temperature reading corresponding to the given information.=-1.475 deg
-2 = 4r + s Subtract 4r from both sides
-2 - 4r = s Switch the sides to make it easier to read
s = -4r -2
