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maksim [4K]
2 years ago
7

You deposit $3000 in a bank account that pays 4% annual interest. Find the balance after 7 years if the interest is compounded q

uarterly.​
Mathematics
1 answer:
Stels [109]2 years ago
7 0

Answer:

$3840.

Step-by-step explanation:

First, write down the formula: I= PRT (Interest= Principle, rate, time). Then you multiply all of the numbers (3000x0.04x7). You get 840, but then you need to add it to the $3000 which already exist, therefor you get your answer of $3840.

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What is the second step to solving this equation?<br> 9x - 23 = 49
Anna11 [10]

Answer:

Divide 9 from both sides.

Step-by-step explanation:

The first step to solving this equation is to add 23 to both sides.

9x - 23 (+23) = 49 (+23)

9x = 49 + 23

9x = 72

The second step is to isolate the x and divide 9 from both sides:

(9x)/9 = (72)/9

x = 72/9

x = 8

~

6 0
3 years ago
What is the range of the function y=3x-2 if the domain is {0,1,2}
soldier1979 [14.2K]

Answer: 2

Step-by-step explanation:

4 0
3 years ago
Ten students share 8 pieces of poster board equally. What fracyion pf a poece of poster board does each student get?
andrew11 [14]
When 1 is divided into 8 pieces, each piece is 1/8 of the whole.
3 0
3 years ago
The triangle below is an equilateral triangle. Find yy = 10y = 180y = 7y = 13
Viktor [21]

Solution

For this case we have the following

y+3 = x = 10

Then x= 10

So we can set up this equation:

y+3 = 10

y= 7

Then the answer is:

y=7

4 0
1 year ago
In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo
larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine z_{\frac{\alpha}{2}}=z_{0.005}

Now by using z score table we find that  z_{\frac{\alpha}{2}}=2.58

The boundaries of the confidence interval are:

\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

3 0
3 years ago
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