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Anna35 [415]
2 years ago
11

22 Simplify the expression below. 9 (-2-8) + (-16)​

Mathematics
2 answers:
MAXImum [283]2 years ago
8 0
-19 + 72 -16
53 - 16
37
ivann1987 [24]2 years ago
5 0
37 dodododododooddiofofodod
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H(x)=1/<br> x-8<br> someone help
GrogVix [38]
Find the domain of the given funciton

domain is numbers you can use in the function for x
so fractions
remember
never divide by 0
find what number makes denomenator 0 and restrict that


x-8=0
x=8

the domain is all real numbers except fo 8
7 0
3 years ago
Every day The burger buns restaurant serves 1/5 of a bottle of cherry soda to the customers for how many days will 1 4/5 bottles
kogti [31]
9 because if you change 1 and 4/5 to an improper fraction and you’ll get 9/5. If you multiply 1/5 by 9 you’ll get 9/5.
5 0
2 years ago
6-11x=7x-12 how do you solve
tekilochka [14]
Use Cymath it helps and give u the answer
6 0
3 years ago
An arhitect wants to draw a rectangle with a diagonal of 20 inches. The length of the rectangle is to be 8 inches more than twic
kiruha [24]

The diagonal of a rectangle = sqrt(w^2 + l^2)

w = width

l = length

In this problem,

The diagonal = 20 in

w = x

l = 2x + 8

Let's plug our numbers into the formula above.

20in = sqrt((x)^2 + (2x + 8)^2)

Let's simplify the inside of the sqrt

20 in = sqrt(5x^2 + 32x + 64)

Now, let's square both sides.

400 = 5x^2 + 32x + 64

Subtract 400 from both sides.

0 = 5x^2 + 32x - 336

Factor

0 = (5x - 28)(x + 12)

Set both terms equal to zero and solve.

x + 12 = 0

Subtract 12 from both sides.

x = -12

5x - 28 = 0

Add 28 to both sides.

5x = 28

Divide both sides by 5

x = 28/5

The width cant be a negative number so now we know that the only real solution is 28/5

Let's plug 28/5 into our length equation.

Length = 2(28/5) + 8 = 56/5 + 8 = 96/5

In conclusion,

Length = 96/5 inches

Width = 28/5

4 0
2 years ago
The recommended single dose for a particular drug is 100 mg. How many doses can be obtained from 20 grams of the drug?
Lisa [10]

Answer:

B. 200 doses

Step-by-step explanation:

Given,

1 dose is required for 100 mg,

Since, 1 mg = 0.001 g,

⇒ 100 mg = 0.1 g

⇒ 1 dost is required for 0.1 g,

Thus, the ratio of doses and quantity ( in gram ) is \frac{1}{0.1}=10

Let x be the doses required for 20 grams,

So, the ratio of doses and quantity is \frac{x}{20}

\implies \frac{x}{20}=10

\implies x=200

Hence, 200 doses can be obtained from 20 grams of the drug.

Option 'B' is correct.

8 0
2 years ago
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