Answer:
d1=2A/d2
d2=2A/d1
Step-by-step explanation:
The options of this question are:
1. d₁=2Ad₂
2. d₁= 2A/d₂
3. d₂= d₁/2A
4. d₁= 2A/d₂
5. d₂= 2Ad₁
Given:
A=1/2(d1*d2)
Multiply both sides by 2
We have,
2A=d1*d2
Divide both sides by d2
2A/d2=d1*d2/d2
2A/d2=d1
Therefore, d1=2A/d2
Similarly, from the previous equation
2A=d1*d2
Divide both sides by d1
2A/d1=d1*d2/d1
2A/d1=d2
Therefore,
d2=2A/d1
Options
2. d₁= 2A/d₂
4. d₁= 2A/d₂
Answer:
The journal entries as well as the T-accounts for August transactions are found in the attached spreadsheet.
Step-by-step explanation:
Initially, the transactions were posted individually in the journal and ultimately the related ones were combined together in the T-accounts.
For instance, cash related transactions are posted in the cash T-account to ascertain the true cash position as at the end of the quarter.
We can take prime numbers so they don't have a common factor other than 1.
3, and 5.
So we have to list the multiples to find the LCM
3: 3, 6, 9, 12,
15, 18
5: 5, 10,
15, 20, 25
15 is the LCM of 3 and 5
So, you can notice that if two numbers, lets call them a and b, have no common factor, then
is the LCM.
Hope that helped :)
According to the hypothesis test, the option that gives the most appropriate method for creating such an estimate is:
A one-sample z-interval for a population proportion.
<h3>What is the hypothesis test?</h3>
He will test if there is enough support to build a new middle school, that is, if the population proportion that supports the building of a new middle school is greater than a threshold.
Only one sample is taken from the district residents, hence the correct option is:
A one-sample z-interval for a population proportion.
You can learn more about hypothesis tests at brainly.com/question/26454209
