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Lyrx [107]
3 years ago
14

How many rows appear in a truth table for the compound proposition: \[(p \leftrightarrow q) \oplus (\neg p \leftrightarrow \neg

r) \wedge \neg q\]
Computers and Technology
1 answer:
AURORKA [14]3 years ago
4 0
Let me re-write the proposition:

p↔q⊕(¬p↔¬r)∧¬q.

Generally, the number of rows in a truth table depends on the number of Variables. Here we have 3 Variables: p,q and r. Each of them can have either the value of 1 or 0, which gives us 2*2*2 possibilities, or 2³, that is 8 possibilities and 8 rows:

p=0, q=0, r=0
p=0, q=0, r=1
p=0, q=1, r=0
p=0, q=1, r=1
p=1, q=0, r=0
p=1, q=0, r=1
p=1, q=1, r=0
p=1, q=1, r=1







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#include <stdio.h>

#include <stdlib.h>

#include <pthread.h>

#include <semaphore.h>

int mcount,wcount;

sem_t x,y,z,wsem,msem,cap;

void delay(void)

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int i;

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delaytime = random();

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sem_wait(&wsem);

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wcount++;

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sem_post(&y);

sem_post(&wsem);

sem_post(&z);

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printf("\twoman out!\n");

sem_post(&cap);  

sem_wait(&y);

wcount--;

if(wcount==0)

{ sem_post(&msem); }

sem_post(&y);

}

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{  

sem_wait(&z);

sem_wait(&msem);

sem_wait(&x);

mcount++;

if(mcount==1)

{ sem_wait(&wsem); }

sem_post(&x);

sem_post(&msem);

sem_post(&z);

sem_wait(&cap);

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sem_post(&cap);

sem_wait(&x);

mcount--;

if(mcount==0)

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int i;

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{

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