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Lyrx [107]
3 years ago
14

How many rows appear in a truth table for the compound proposition: \[(p \leftrightarrow q) \oplus (\neg p \leftrightarrow \neg

r) \wedge \neg q\]
Computers and Technology
1 answer:
AURORKA [14]3 years ago
4 0
Let me re-write the proposition:

p↔q⊕(¬p↔¬r)∧¬q.

Generally, the number of rows in a truth table depends on the number of Variables. Here we have 3 Variables: p,q and r. Each of them can have either the value of 1 or 0, which gives us 2*2*2 possibilities, or 2³, that is 8 possibilities and 8 rows:

p=0, q=0, r=0
p=0, q=0, r=1
p=0, q=1, r=0
p=0, q=1, r=1
p=1, q=0, r=0
p=1, q=0, r=1
p=1, q=1, r=0
p=1, q=1, r=1







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Write a program that takes an integer n as a parameter and sums all of the multiples of 2 or 5 from 1 to n. For example, if n =
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Answer:

// here is code in c++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

// variable

int num;

int tot_sum=0;

cout<<"enter a number: ";

// read the value of n

cin>>num;

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for(int x=1;x<=num;x++)

{

// if multiple of 2 or 5 then add them

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       tot_sum=tot_sum+x;

   }

}

// print the sum

cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;

return 0;

}

Explanation:

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Output:

enter a number:11

sum of multiple of 2 or 5 is:35

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