As a ratio in simplest form, 33.5% is express as

QUESTION IS DOW BELOW 5 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP

masha68 [24]

The central angle in the circle is ∠DAC,major arc is BED, minor arc is ADC and BC=(5π*BD)/18.

Given that BD is diameter of the circle and angle BAC is 100°.

We are required to find the central angle, major arc, minor arc, m BEC, BC.

Angle is basically finding out the intensity of inclination of something on the surface.

In the circle central angles are many like BAC and CAD. We can write CAD as DAC also.

Major arc of a circle is that arc whose length is larger than all other arcs in the circle.

In our circle the major arc is arc BED.

Minor arc of a circle is that arc whose length is smaller.

In our circle the minor arc is arc ADC.

We know that arc's length is 2πr(Θ/360)

In this way BC=2π*(BD/2)*100/360

=(5π*BD)/18

We cannot find angle BEC.

Hence the central angle in the circle is ∠DAC,major arc is BED, minor arc is ADC and BC=(5π*BA)/18.

Learn more about angles at brainly.com/question/25716982

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7 0

2 years ago

Factor and find the zeros. z^2-z+56

Inessa [10]

Answer:

Sry its long but if your to lazy to look thru it here is the answer= z = {-7, 8}

Step-by-step explanation:

Simplifying

z2 + -1z + -56 = 0

Reorder the terms:

-56 + -1z + z2 = 0

Solving:

-56 + -1z + z2 = 0

Solving for variable 'z'.

Factor a trinomial.

(-7 + -1z)(8 + -1z) = 0

Subproblem 1

Set the factor '(-7 + -1z)' equal to zero and attempt to solve:

Simplifying:

-7 + -1z = 0

Solving:

-7 + -1z = 0

Move all terms containing z to the left, all other terms to the right.

Add '7' to each side of the equation.

-7 + 7 + -1z = 0 + 7

Combine like terms: -7 + 7 = 0

0 + -1z = 0 + 7

-1z = 0 + 7

Combine like terms: 0 + 7 = 7

-1z = 7

Divide each side by '-1'.

z = -7

Simplifying:

z = -7

Subproblem 2

Set the factor '(8 + -1z)' equal to zero and attempt to solve:

Simplifying:

8 + -1z = 0

Solving:

8 + -1z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + -1z = 0 + -8

Combine like terms: 8 + -8 = 0

0 + -1z = 0 + -8

-1z = 0 + -8

Combine like terms: 0 + -8 = -8

-1z = -8

Divide each side by '-1'.

z = 8

Simplifying:

z = 8

Solution

z = {-7, 8}

4 0

2 years ago

The area of the postcard is 24 square inches. What is the width b of the message (in inches)?

MAXImum [283]

Area of rectangular post card = length x width
For the given post card:
length = 4 in
width = (3+b) in
area = 24 in^2

So, substituting in the equation of the area:
24 = 4 x (3+b)
24 = 12 + 4b
24 - 12 = 4b
12 = 4b
b = 3 in

Therefore:
the length of the postcard = 4 inch
the width of the postcard = b+3 = 3 + 3 = 6 inch

4 0

3 years ago

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t),

pishuonlain [190]

Answer:

S(3)=22

Step-by-step explanation:

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t).

$\dfrac{dS}{dt}=k(30-S(t))\\ \dfrac{dS}{dt}+kS(t)=30k\\$The integrating factor: e^{\int k dt}=e^{kt}\\$Multiply all through by the integrating factor\\ \dfrac{dS}{dt}e^{kt}+kS(t)e^{kt}=30ke^{kt}$

$(Se^{kt})'=30ke^{kt} dt\\$Integrate both sides\\ Se^{kt}=\dfrac{30ke^{kt}}{k}+C$ (C a constant of integration)\\Se^{kt}=30e^{kt}+C\\$Divide both sides by e^{kt}\\S(t)=30+Ce^{-kt}$

When t=0, S(t)=15

$15=30+Ce^{-k*0}\\C=15-30\\C=-15$

When t = 2, S(t)=20

$20=30-15e^{-2k}\\20-30=-15e^{-2k}\\-10=-15e^{-2k}\\e^{-2k}=\dfrac23\\$Take the natural log of both sides$\\-2k=\ln \dfrac23\\k=-\dfrac{\ln(2/3)}{2}$

Therefore:

$S(t)=30-15e^{\frac{\ln(2/3)}{2}t}\\$When t=3$\\S(t)=30-15e^{\frac{\ln(2/3)}{2} \times 3}\\S(3)=21.8 \approx 22$

8 0

2 years ago

what is the quotient when x3 − 5x2 2x 5 is divided by x − 2? x2 − 3x − 4 x2 − 7x 16 x2 − 3x − 4 − 3 over the quantity of x minus

nekit [7.7K]

The correct answer is: 
x²-3x-4 - $\frac{3}{x-2}$ .

Explanation: 
To divide these polynomials, the dividend, x³-5x²+2x+5, goes under the box, and the divisor, x-2, goes outside of the box.

We first want to find what we multiply x by to make x³; x*x²=x³, so we write x² over -5x² in the box.

Now we multiply our divisor, x-2, by x²: 
x*x²=x³
-2*x²=-2x².

This goes under x³-5x² in the box.

Now we subtract: 
(x³-5x²)-(x³-2x²)=-3x².

This goes below the 2x² we wrote, and we bring down 2x.

Now we see what we multiply x by to make -3x²;
x*-3x=-3x², so we write -3x beside x² in the quotient (at the top).

We multiply our divisor, x-2, by -3x: 
x*-3x=-3x²
-2*-3x=6x.

We write -3x²+6x under our -3x²+2x and subtract:
(-3x²+2x)-(-3x²+6x)=-4x.

Write this below 6x. Bring down +5.

Now we see what we multiply x by to make -4x;
x*-4=-4x, so write -4 beside -3x in the quotient.

Multiply our divisor, x-2, by -4: 
x*-4=-4x;
-2*-4=8;

write -4x+8 below -4x+5 and subtract:
(-4x+5)-(-4x+8)=-3.

This gives us the quotient x²-3x-4 with a remainder of -3, so we write our full answer as x²-3x-4-(3/x-2).

3 0

3 years ago

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