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qaws [65]
2 years ago
15

Find the 11th term of the arithmetic sequence -2x,-8,-9x,-11,-16x,-14

Mathematics
1 answer:
Valentin [98]2 years ago
5 0

Answer:

in an arithmetic series, an = a0+ (n-1) *d

 

that means the nth term is equal to the first term plus n-1 times the common difference.

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F(x) = –16x2 24x 16
evablogger [386]
The x-intercepts are: -0.5 and 2.
3 0
2 years ago
A toy company makes rectangular sandboxes that measure 6 feet by 5 feet by 1.2 feet. A customer buys a sandbox and 40 cubic feet
Iteru [2.4K]

Answer:

Customer has bought too much sand

Step-by-step explanation:

Given that the dimensions (Length, Width and Height) of rectangular box are = 6,5, 1.2.

Volume of a rectangular box = Length * Width * Height

=> 6*5*1.2

=> 36 cubic feet

As mentioned, customer bought a sand box and <u>40 cubic feet of sand.</u>

So,

Volume of rectangular box (R) = 36 cubic feet

Volume of Sand (S) = 40 cubic feet

From analysis

S > R

Which shows that the capacity of sandbox is 36 cubic feet and volume is 40 feet that is a little greater than desired capacity.

Therefore, customer has bought too much sand.

4 0
3 years ago
Write 1.6 x 10 in standard form.
ddd [48]
The answer is 16000000000.
Because you take the decimal and move it 10 times to the right.
8 0
3 years ago
Read 2 more answers
If y=27 when x= 8 find y when x =11
Rina8888 [55]

Answer:

37 1/8

Step-by-step explanation:

The problem probably assumes direct variation

y=kx

IF so, then plug in the values and solve for k

27=k(8)

k = 27/8

y= (27/8)x.  Now let x = 11

y = (27/8)11 = 27(11)/8 = 37.125 = 37 1/8

y = 37 1/8

the problem is making some assumption about the relation between x and y.  The simplest assumption that's likely is direct variation,  that x and y are linearly related.  The graph is a straight line through the origin with slope = 27/8

6 0
2 years ago
An instructor who taught two sections of engineering statistics last term, the first with 20 students and the second with 30, de
Lelechka [254]

Answer:

(a) P(X=10) = 0.2070

(b) P(X\geq 10) = 0.3798

Step-by-step explanation:

Note that in this problem we have an initial population N = 50, of which 30 fulfill a certain characteristic "m" (belong to the second section). Then, from the population N, a sample of size n = 15 is selected and it is desired to know how many comply with the desired characteristic (second section).

So

Let X be the number of projects in the second section, then X is a discrete random variable that can be modeled by a hypergeometric distribution.

(a)

Therefore, to answer question (a) we use the following equation presented in the attached image:

Where:

N = 50\\m = 30\\n = 15\\X = 10

Then:

P (X = 10) = \frac{\frac{30!}{10!(30-10)!}\frac{20!}{5!(20-5)!}}{\frac{50!}{15!(50-15)!}}\\\\\\P(X=10) = 0.2070

(b)

For part (b) we have:

P(X\geq10) = 1-P(X

P(X\geq 10) = 1-0.6202 \\\\P(X\geq 10) = 0.3798

4 0
3 years ago
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