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3 years ago

F(x) = x − 3 and g(x) = 2x + 8 Which ordered pair is a solution for the system?

Mathematics

2 answers:

Phoenix [80]3 years ago

8 0

I put it into Desmos and got (-11, -14)

kondor19780726 [428]3 years ago

6 0

$f(x)=g(x)\to x-3=2x+8\qquad\text{add 3 to both sides}\\\\x=2x+11\qquad\text{subtract 2x from both sides}\\\\-x=11\to\boxed{x=-11}\\\\\text{Put the value of x to the equation of f(x):}\\\\f(-11)=-11-3=-14\\\\Answer:\ \boxed{x=-11\ and\ y=-14\to(-11,\ -14)}$

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59% of 640. We are supposed to find the percent of each number (as you can see)

Novosadov [1.4K]

Answer:

377.6

Step-by-step explanation:

Multiply 59 by 640 and then move the decimal point over two numbers.

59% of 640

59 x 640

37760.0

377.6

4 0

3 years ago

suppose Q is the midpoint of PR. use the information to find the missing value. PQ equals 3x + 14 and QR equals 7X - 10; find X.

NARA [144]

Answer:

x=6

Step-by-step explanation:

A midpoint is the middle point of a line segment, therefore it is equal distances from both ends of the segment.

This means that PQ and QR have the same length. So all we have to do is set each value equal to each other, and then solve for X.

$3x+14=7x-10\\3x+24=7x\\24-4x\\x=6$

4 0

3 years ago

Read 2 more answers

25 POINTS PLEASE PLEASE HELPPPP, ALSO THE QUESTION IS WORTH 4 MARKS SO PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELPPPPP

patriot [66]

So u already know that the radius is half of the circle which in this case is 28 mm. And both circles at the top touch both sides of the rectangle.
Process:
28x4=112.
This is the top side, but because you could fit 2 circles at the top and you know the measurement, it is common sense to think that it would be the same on the other side. So the area of the square/ rectangle:
112x112= 12,534 mm

5 0

3 years ago

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

Note: Since you missed to mention the the expression of the function $p(x)$ . After a little research, I was able to find the complete question. So, I am assuming the expression as $p(x)=x^4-9x^2-4x+12$ and will solve the question based on this assumption expression of $p(x)$ , which anyways would solve your query.

Answer:

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial $p(x)=x^4-9x^2-4x+12$

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say $p(x)$ , $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ , we must have to evaluate $p(x)$ for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$