<h3>Given</h3>
S = πr√(r^2+h^2)
h = 8 m (constant)
<h3>Find</h3>
An approximation of S when r changes from 9 to 8.9
<h3>Solution</h3>
Such an approximation is usually made by estimating the change using the first derivative. That derivative with respect to r is
... S' = π√(r^2+h^2) + πr(1/2·r)/√(r^2+h^2)
... S' = π(2r^2 +h^2)/√(r^2 +h^2) . . . . . use a common denominator
For r=9, h=8, this is
... S' = π(2·81 +64)/√(81+64) = 226π/√145 ≈ 58.96
Then the change in lateral surface area will be approximately
... ∆S ≈ (∆r)·S' ≈ (-0.1)·(58.96) ≈ -5.90 . . . m²
Answer:
-2°F>-5°F
Step-by-step explanation:
-2°F is greater than -5°F
This also means the first time Mrs. Ortiz measured the outside tempurature it was hotter than the second time she measured it.
Answer:
answer C.
Step-by-step explanation:
it has the most logical explanation, frankly I'm not the best with circles, but I'm decently sure I'm right
Answer:
first option
Step-by-step explanation:
∠CAD ≅ ∠ACB from the diagram and because they are alternate interior angles, AD || BC because of the Converse of the Interior Angles Theorem.