Answer:
The area of the shape after it has been enlarged by
scale factor 2 will be: 10 cm²
Step-by-step explanation:
The Area is basically a measure of how much space in square units there is inside an object.
As the shape is shown on the centimeter grid.
- The shape clearly occupies the space of 5-centimeter squares.
We also know that If the scale factor > 1, the image is enlarged.
As we know to determine the area of the shape after it has been enlarged by scale factor 2, all we need to do is to multiply the area of the original shape by 2.
The area of original shape = 5 cm²
The area of the shape after the dilation by a scale factor 2 = 5 × 2 = 10 cm²
Thus, the area of the shape after it has been enlarged by
scale factor 2 will be: 10 cm²
Answer:
g/cm²
Step-by-step explanation:
First, we need to find the volume of the prism. The volume of a square pyramid is V = Bh/3
B = 100 cm²
h = 6 cm
V = 100 cm² * 6 cm /3
V = 600 cm³ /3
V = 200 cm³
Next, we need to solve for the density based on the desired volume and mass.
m = mass = 300 g
V = volume
density = m/V
density = 300 g / 200 cm³
density = 3/2 g/cm³
The lowest possible density of the material to make the paperweight would be
g/cm²
<u>Explanation</u><u>:</u>
Consider ABCD is a rhombus
We know that
All sides are equal in rhombus i.e,
⇛AB=BC=CD=DA
and AC and BD are digonals
Given that
Diagonal and the side of the rhombus are equal.
⇛AB = BC = CD = DA = AC
Diagonal AC divides the rhombus into two triangles .
They are ∆ BAC and ∆ DAC
In triangle BAC
BA=BC=AC,(Given)
⇛∠ BAC=∠ABC= ∠ACB =60°→→→Eqn(i)
Similarly in ∆DAC ,
DA=DC=AC
⇛∠DAC=∠ACD=∠ADC=60°→→→Eqn(ii)
From eqn(i) and eqn(ii)
∠A=∠BAC+∠DAC=60°+60°=120°
and
∠B= ∠ABC = 60°.
and
∠C=∠ACB+∠ACD=60°+60°=120°
and
∠D =∠ADC=60°
∴ ∠A = 120° , ∠B = 60° ,∠C = 120° & ∠D = 60°
<u>Answer:</u><u>-</u>The measures of the all angles in the rhombus are 120° , 60° ,120° and 60°.
Note: [Figure refers in the attached file.
Answer:
Step-by-step explanation:
a) Denote the event of commercially availability of f_uel cell technology as F_, commercial availability of solar power technology as S
Write the probability of energy supplied by these energy sources in the next 10 years
P(energy supplied) = P(S ∪ F) -----(1)
Rewrite eqn (1)
P(energy supplied) = P(S) + P(F) - P(F) P(S) ----(2)
substitute 0.85 for P(S) and 0,7 for P(F) in eqn (2) to find the probability of energy supplied by these energy sources
P(energy supplied) = 0.85 + 0.7 - (0.7 * 0.85)
= 0.85 + 0.7 - (0.595)
= 1.55 - 0.595
= 0.955
Therefore, the probability that there will be energy supplied by these two alternative sources in the next 10 years is 0.955
B) write the probability of only one source of energy available
P(only one source of energy available) =
∪
---(3)
Rewrite the equation (3)
P(only one source of energy available) =
![=P(\bar F S)+P(\bar S F)\\\\=\{[1-P(F)]P(S)+[1-P(S)]P(F)\}---(4)](https://tex.z-dn.net/?f=%3DP%28%5Cbar%20F%20S%29%2BP%28%5Cbar%20S%20F%29%5C%5C%5C%5C%3D%5C%7B%5B1-P%28F%29%5DP%28S%29%2B%5B1-P%28S%29%5DP%28F%29%5C%7D---%284%29)
![=\{[1-0.7]0.85+[1-0.85]0.7\}\\\\=0.255+0.105\\\\=0.36](https://tex.z-dn.net/?f=%3D%5C%7B%5B1-0.7%5D0.85%2B%5B1-0.85%5D0.7%5C%7D%5C%5C%5C%5C%3D0.255%2B0.105%5C%5C%5C%5C%3D0.36)
Therefore,The probability that only one of the two alternative energy sources will be commercially viable in the next 10 years is 0.36