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Arisa [49]
3 years ago
7

Find the total surface area of this square based pyramid

Mathematics
2 answers:
Masteriza [31]3 years ago
8 0

Answer:

300ft²

Step-by-step explanation:

base=LW = 10x10=100

triangles=1/2bh = 1/2(10)(10)=50 (4 of them)

100+4(50)=

100+200=300ft²

Shkiper50 [21]3 years ago
8 0

Answer:

300 ft²

Step-by-step explanation:

Surface area= area of base + 4*area of triangle

a= 10 ft

h= 10 ft

<u>Surface area:</u>

  • 10*10+ 4*1/2*10*10= 300 ft²
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Cindy is going to order some packets of seeds. The cost, c, of an order of n packets of seeds is given by the equation c equal 4
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Answer:

c

Step-by-step explanation:

i took the test

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3 years ago
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7) Order the numbers from least to greatest.<br> A. 6.66<br> B. 6.07<br> C. 7<br> D. 6.32
jek_recluse [69]

the Answear is B,D,A,C

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3 years ago
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The original price of a computer game is 45$ The price is marked down by 18$ what percent of the original price is the markdown?
OLga [1]

Answer:

$27

Step-by-step explanation:

$45 - $18 = $27

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4 0
2 years ago
Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution
Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\

for y=e^{6x}:

y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\

Now we replace in the differential equation  y'' − y' − 30y = 0

for y=e^{-5x}:

25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0

for y=e^{6x}:

36e^{6x}-6e^{6x}-30=0\\36-6+30=0

Now, to know if both function are linearly independent we calculate the Wronskian

W(f,g)=fg'-f'g

W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0

I hope this is useful for you

Best regard

7 0
4 years ago
The students in a science class spent 65% of the class period performing an experiment. how long is a class period if the time s
Kaylis [27]
We let x be the length (in minutes) of a certain science class. 65% of this period is spent with the experiment which lasted for about 52 minutes. Mathematically, this can be expressed as,
                                    52 = (0.65)(x)
The value of x from the generated equation is 80. Thus, the science class is 80 minutes long. 
7 0
4 years ago
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