B is the answer because you have to math it
This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,
4C3 = 4!/3!(4 - 3)! = 4 ways
If you want to get 2 green out of the total 6, then that would be 6C2. That means,
6C2 = 6!/2!(6-2)! = 15 ways
Therefore, there are a total of 4+15 = <em>19 ways</em>.
C, if there is an odd number of negatives it is negative, if there is an even number it is positive
Answer:
The answer is D: only I and II
Step-by-step explanation:
I know for sure this is the correct answer. Hope this helped! Mark me Brainliest!
