Answer:
See picture and explanation below.
Step-by-step explanation:
With this information, the matrix A that you can find is the transformation matrix of T. The matrix A is useful because T(x)=Av for all v in the domain of T.
A is defined as ![T=([T(v_1)] [T(v_2] [T(v_3)])\text{ where }[T(v_i)]](https://tex.z-dn.net/?f=T%3D%28%5BT%28v_1%29%5D%20%5BT%28v_2%5D%20%5BT%28v_3%29%5D%29%5Ctext%7B%20where%20%7D%5BT%28v_i%29%5D)
denotes the vector of coordinates of 
respect to the basis 
(we can apply this definition because 
forms a basis for the domain of T).
The vector of coordinates can be computed in the following way: if 
then ![[T(v_i)]=(a_1,a_2,a_3)^t](https://tex.z-dn.net/?f=%5BT%28v_i%29%5D%3D%28a_1%2Ca_2%2Ca_3%29%5Et)
.
Note that we have all the required information: 
then ![[T(v_1)]=(0,1,0)^t](https://tex.z-dn.net/?f=%5BT%28v_1%29%5D%3D%280%2C1%2C0%29%5Et)
hence ![[T(v_2)]=[T(v_3)]=(1,0,0)^t](https://tex.z-dn.net/?f=%5BT%28v_2%29%5D%3D%5BT%28v_3%29%5D%3D%281%2C0%2C0%29%5Et)
The matrix A is on the picture attached, with the multiplication A(1,1,1).
Finally, to obtain the output required at the end, use the properties of a linear transformation and the outputs given:
In this last case, we can either use the linearity of T or multiply by A.
The bottom answer matches. please give brainlest
Answer:
y= 4x − 7 or 0=0
Step-by-step explanation:
4x−y+−4x=7+−4x
Hi there!
Assuming "Find the product" means multiplying (4x-3) by (3x+8) and factor to it's simplest form the answer would be:
12x²+23x-24
The way you solve this is by using the distributive property of multiplication as shown below:
Start by multiplying -3 from (4x-3) by everything in (3x+8)
3x*(-3) = -9x
8*(-3) = -24
Once you've done that you then multiply everything 4x
4x*8 = 32x
4x*3x = 12x²
(Note: when multiplying two of the same variables like x it means you are multiplying x by itself which is the same as x²)
When you put all of this together it looks like this
12x²+32x-9x-24
from there we combine like terms
32x-9x = 23x
to get
12x²+23x-24
I hope this helps!
God bless,
ASIAX
