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a_sh-v [17]
3 years ago
8

A spherical fish bowl is half-filled with water. The center of the bowl is C, and the length of segment AB is 16 inches, as show

n below. Use Twenty two over seven for pi.
A sphere with diameter 16 inches is drawn.

Which of the following can be used to calculate the volume of water inside the fish bowl?

1 over 24 over 322 over 7(82)(16)
1 over 24 over 322 over 7(83)
1 over 24 over 322 over 7(162)(8)
1 over 24 over 322 over 7(163)

Mathematics
2 answers:
svetlana [45]3 years ago
8 0

Answer:

B. \frac{1}{2}\times\frac{4}{3}\times \frac{22}{7}\times 8^3

Step-by-step explanation:

We have been given that a fish bowl has a diameter of 16 inches. We are asked to find the half-volume of the water inside the fish bowl.

We will use volume of sphere formula to solve the given problem.

\text{Volume of sphere}=\frac{4}{3}\pi r^3, where r represents radius of sphere.

Let us figure out radius of fish bowl by dividing its diameter by 2 as:

r=\frac{16}{2}=8

\text{Volume of half filled fish bowl}=\frac{1}{2}\times\frac{4}{3}\times \frac{22}{7}\times r^3

\text{Volume of half filled fish bowl}=\frac{1}{2}\times\frac{4}{3}\times \frac{22}{7}\times 8^3

Therefore, option B is the correct choice.

gayaneshka [121]3 years ago
7 0

Answer:

The second choice

1 over 2/4 over 3/22 over 7/(8^{3})

Step-by-step explanation:

we know that

The volume of a sphere is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

r=16/2=8\ in

\pi=22/7

To find the volume of water calculate the volume of semi-sphere

so

V=\frac{1}{2}\frac{4}{3}\pi r^{3} ------> volume of semi-sphere

substitute the values

V=\frac{1}{2}\frac{4}{3}(\frac{22}{7})(8)^{3}      

1 over 2/4 over 3/22 over 7/(8^{3})


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