The number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles
The Company A rented the truck for $40 a day plus $0.40 per miles
The expression will be
40+0.40x
Where x is the number of miles
The company B rented the truck for $20 a day plus $0.50 per miles
20+0.50x
To find the number of miles in a day at which the rental costs for Company A and Company B are the same, the linear equation will be
40+0.40x = 20+0.50x
40-20 = 0.50x-0.40x
0.1x = 20
x = 200 miles
Hence, the number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles
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The remainder is 9........
The answer must be a whole number because for example how are you suppose to fit half a child on a bus that can hold 44 people when it already holds that amount.
It will always be a whole number because if there are several left over students they will be put in another bus with more empty seats.
Answer:
9 + 10 +x= 21
x=21-19
x=2
add 2 in left hand side to get 21
18%=0.18
380×0.18=68.4 increase
380+68.4=448.4
the easier way is to think 1 times any number is the same number so 380(1+0.18)=448.4 (just like adding tax to the price of something to see how much you'll actually pay)
