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Rashid [163]
3 years ago
5

The graphs of f(x) and g(x) are shown below.

Mathematics
2 answers:
nexus9112 [7]3 years ago
7 0

Answer:

On a coordinate plane, a straight line with a positive slope goes through points (negative 2, negative 6), (0, 0), and (2, 6).

Step-by-step explanation:

The function is given by f(x) = - x and another function is given by g(x) = 2x.

Now, (g - f)(x) will be given by

(g - f)(x) = 2x - (- x) = 3x .......... (1)

Now, we have to choose from the options of the graphs that is applicable to function (1).

So, on a coordinate plane, a straight line with a positive slope goes through points (negative 2, negative 6), (0, 0), and (2, 6). (Answer)

Alex73 [517]3 years ago
7 0

Answer:

Option C

Step-by-step explanation:

We are given that

f(x)=-x

The line passing through the points (0,0),(-6,6) and (6,-6).

g(x)=2x

The line passing through the points (-3,-6),(0,0) and (3,6).

We have to find the graph of (g-f)(x).

(g-f)(x)=g(x)-f(x)=2x-(-x)=2x+x

(g-f)(x)=3x

Substitute x=0

(g-f)(0)=3(0)=0

(g-f)(2)=3(2)=6

(g-f)(-2)=3(-2)=-6

(g-f)(-6)=3(-6)=-18

Option C is true.

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Answer:

The area of a parallelogram is 360 in.²

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AB = 39 in.

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Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

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We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

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Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

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