Answer:
c) 256
Step-by-step explanation:
https://www.tiger-algebra.com/drill/x/32=8/ This link shows you how it’s done, it’s not some random link, i used the website all the time
All of these sets meet the requirements of the triangle inequality. The sum of any two numbers in the set is greater than the third one. (You really only need to check that the sum of the smallest two is greater than the largest.)
It can help to resolve the numbers that are only indicated as to value.
√13 ≈ 3.606
2√10 ≈ 6.325
_____
Your comparisons can be ...
2 + 3 = 5 > 3.606 . . . is a triangle
5 + 5 = 10 > 6.325 . . . . . . is a triangle
5 + 12 = 17 > 15 . . . . . . . . is a triangle
Answer:
3xy² - 14y²
Step-by-step explanation:
I hope that this is the problem
- x²y + [ - (x²y - 2xy² + y²) + (xy² - 3y² + x²y)] - (10y² - x²y)
= - x²y + [ - x²y + 2xy² - y² + xy² - 3y² + x²y] - 10y² + x²y
Now combine like terms in the [ ].
= - x²y + [ -x²y + x²y + 2xy² + xy² - y² - 3y² ] - 10y² + x²y
= - x²y + [ 0 + 3xy² - 4y²] - 10y² + x²y
= - x²y + 3xy² - 4y² -10y² + x²y Now combine like terms
= (-x²y + x²y) + 3xy² + (-4y² - 10y²)
= 0 + 3xy² - 14y²
= 3xy² - 14y² or y²(3x - 14)
Answer:
(x,y)=(0,7.333)
Step-by-step explanation:
We are required to:
Maximize p = x + 2y subject to
- x + 3y ≤ 22
- 2x + y ≤ 14
- x ≥ 0, y ≥ 0.
The graph of the lines are plotted and attached below.
From the graph, the vertices of the feasible region are:
At (0,7.333), p=0+2(7.333)=14.666
At (4,6), p=4+2(6)=4+12=16
At (0,0), p=0
At (7,0), p=7+2(0)=7
Since 14.666 is the highest, the maximum point of the feasible region is (0,7.333).
At x=0 and y=7.333, the function p is maximized.