1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anuta_ua [19.1K]
3 years ago
11

SIENCE! help please its due yesterday and i didn’t do it :(

Physics
2 answers:
kondor19780726 [428]3 years ago
6 0

Answer:  H

the lights travel through the mirr to create a bigger wider light.

hope this helps (:

Mariulka [41]3 years ago
4 0
I believe it could be H
You might be interested in
How many electrons are in an Sn+2 ion?
Veseljchak [2.6K]

Sn is Tin which has 50 atomic number

it means it has 50 electrons in its outer shells

+2 shows its valency

plus sign comes when electrons are removed from an atom

so here 2 electrons are removed from Sn atom

remaining electrons are 50-2

48 electrons

6 0
4 years ago
Read 2 more answers
A ship is towed through a narrow channel by applying forces to three ropes attached to its bow. Determine the magnitude and orie
Y_Kistochka [10]

This question is solved using an available similar problem as data provided for the forces was not given.

Repeat the same steps outlined for your problem.

Regards.

Answer:

F = 1.598 KN , Q = 90 degree (+ y-axis)

Explanation:

Sum of Forces in x-direction to the left (+)

2 cos (30) + 3cos (60) + F*cos (Q) = F_a   ..... 1

Sum of Forces in y-direction to the up (+)

2 sin (30) + F*sin (Q) - 3 sin (60)  ...... 2

Using Eq 2 and solve:

F*sin (Q) = 1.598 KN

F_min when sin (Q) is max, max possible value of sin(Q) = 1 @ Q = 90 degrees.

Hence,

F_min = 1.598 KN

Using Eq 1 @ Q = 90 degrees and F = 1.598 KN:

F_a = 2 cos (30) + 3cos (60)  = 3.2 KN

6 0
3 years ago
The object has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 microme-
olasank [31]

b. The wavelength of light emitted by the object is 233 nm

c. The type of radiation originally emitted by the object is ultraviolet radiation.

To find the wavelength, we need to know what redshift is.

<h3>What is redshift?</h3>

Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.

Redshift is given by z = λ'/λ - 1 where

  • λ' = observed wavelength and
  • λ = emitted wavelength.

Making λ subject of the formula, we have

λ = λ'/(1 + z)

Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).

So,

  • z = 7.6 and
  • λ' = 2μm

<h3>(b) What is the wavelength of the light emitted by the object?</h3>

Substituting the values of the variables into the equation, we have

λ = λ'/(1 + z)

λ = 2μm/(1 + 7.6)

λ = 2μm/8.6

λ = 0.233 μm

λ = 233 nm

So, the wavelength of light emitted by the object is 233 nm

<h3>c. What type of radiation was originally emitted by the object?</h3>

Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.

So, the type of radiation originally emitted by the object is ultraviolet radiation.

Learn more about redshift here:

brainly.com/question/27915180

#SPJ1

8 0
3 years ago
What is the force if the mass is 75kg and the acceleration is 24.5m/s^2
Snowcat [4.5K]

<u>Given;</u>

mass m = 75 kg

acceleration a = 24.5 ms²

<em>F = ma </em>

F  =  75 kg * 24.5 ms²

    =  1837.5 kg ms².

4 0
3 years ago
A car moves at a constant velocity of 30 m/s and has 3.6 × 105 J of kinetic energy. The driver applies the brakes and the car st
LekaFEV [45]

The force needed to the stop the car is -3.79 N.

Explanation:

The force required to stop the car should have equal magnitude as the force required to move the car but in opposite direction. This is in accordance with the Newton's third law of motion. Since, in the present problem, we know the kinetic energy and velocity of the moving car, we can determine the mass of the car from these two parameters.

So, here v = 30 m/s and k.E. = 3.6 × 10⁵ J, then mass will be

K.E = \frac{1}{2} * m*v^{2}  \\\\m = \frac{2*KE}{v^{2} } = \frac{2*3.6*10^{5} }{30*30}=800 kg

Now, we know that the work done by the brake to stop the car will be equal to the product of force to stop the car with the distance travelled by the car on applying the brake.Here it is said that the car travels 95 m after the brake has been applied. So with the help of work energy theorem,

Work done = Final kinetic energy - Initial kinetic energy

Work done = Force × Displacement

So, Force × Displacement = Final kinetic energy - Initial Kinetic energy.

Force * 95 = 0-3.6*10^{5}\\ \\Force =\frac{-3.6*10^{5} }{95}=-3.79 N

Thus, the force needed to the stop the car is -3.79 N.

5 0
3 years ago
Other questions:
  • 1). What % of the surface of the earth is covered by water!
    8·1 answer
  • Consider a thermometer at room temperature 20.0 ◦C. We now place it inside a water tank whose temperature is at 30.0 ◦C. After o
    5·1 answer
  • The neurons of giant squids, for example, consist of axons with very large radii, which allows the squid to react very quickly w
    15·1 answer
  • One celled organisms that reproduce by fission?
    11·2 answers
  • A cork able to float on water because it is
    14·1 answer
  • There are two groups of waves with the same amplitude. One contains waves of short wavelength and the other has waves of long wa
    7·1 answer
  • Measure the mass of a coin using a triple beam balance.
    12·1 answer
  • Which of the following decreases the dissolving rate of a solid in water?
    14·2 answers
  • Motion according to Albert Einstein​
    6·1 answer
  • What will be net force be if net forces are unbalanced?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!