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JulijaS [17]
3 years ago
5

Consider a thermometer at room temperature 20.0 ◦C. We now place it inside a water tank whose temperature is at 30.0 ◦C. After o

ne minute, it shows the temperature at 29.8 ◦C.
(a) Assuming the thermometer follows a 1st-order dynamics, what is its time constant?
(b) If we place the same thermometer in another tank whose temperature increases linearly with a uniform rate of 2◦C/min, and we wait long enough, what would be the measurement error (in ◦C) in the thermometer reading?
Physics
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

jhvkb

Explanation:

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5 0
3 years ago
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Freud believes that defense mechanisms are reactions people have to protect themselves from uncomfortable feelings. the article
makkiz [27]

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A: Anxious

Explanation:

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6 0
2 years ago
An insulated beaker with negligible mass contains 0.250 kg of water at 75.0C. How many kilograms of ice at -20.0C must be droppe
kkurt [141]

Answer:

The amount of kilograms of ice at -20.0°C that must be dropped into the water to make the final temperature of the system 40.0°C = 0.0674 kg

Explanation:

Heat gained by ice in taking the total temperature to 40°C = Heat lost by the water

Total Heat gained by ice = Heat used by ice to move from -20°C to 0°C + Heat used to melt at 0°C + Heat used to reach 40°C from 0°C

To do this, we require the specific heat capacity of ice, latent heat of ice and the specific heat capacity of water. All will be obtained from literature.

Specific heat capacity of ice = Cᵢ = 2108 J/kg.°C

Latent heat of ice = L = 334000 J/kg

Specific heat capacity of water = C = 4186 J/kg.°C

Heat gained by ice in taking the total temperature to 40°C = mCᵢ ΔT + mL + mC ΔT = m(2108)(0 - (-20)) + m(334000) + m(4186)(40 - 0) = 42160m + 334000m + 167440m = 543600 m

Heat lost by water = mC ΔT = 0.25 (4186)(75 - 40) = 36627.5 J

543600 m = 36627.5

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3 0
3 years ago
A voltage of 220V (rms) line to netralvoltage is applied across a three phase Y connected resistive load. Each phase of the Y co
mrs_skeptik [129]

Answer:

Current through each phase Vp = 2.2A

Total three phase power Pt= 1.45kW

Power factor of the load pf = 1

Explanation:

i) Find current through each phase

Vp =220V (rms)

Z =100 Ω

I = Vp/Z

 = 220/100

 = 2.2A

ii) Find the total three phase power

for a resistive load, Power, P = VI

Power for each phase is given as:

P = 220 * 2.2

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Total power TP =3* P

                          =484*3

                          = 1452W

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 iii) Find the power factor of the load

Phase angle for a resistive load is 0.

α= 0

Hence, power factor of load = cos α

                                          pf      = cos 0

                                             pf    = 1

5 0
3 years ago
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timama [110]

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

a =  \frac{f}{m}

4 0
3 years ago
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