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JulijaS [17]
3 years ago
5

Consider a thermometer at room temperature 20.0 ◦C. We now place it inside a water tank whose temperature is at 30.0 ◦C. After o

ne minute, it shows the temperature at 29.8 ◦C.
(a) Assuming the thermometer follows a 1st-order dynamics, what is its time constant?
(b) If we place the same thermometer in another tank whose temperature increases linearly with a uniform rate of 2◦C/min, and we wait long enough, what would be the measurement error (in ◦C) in the thermometer reading?
Physics
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

jhvkb

Explanation:

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A car accelerates uniformly from rest at a speed of 1.67 ft s^2 over a distance of 5 yards.What is the acceleration of a car?
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Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

A car accelerates uniformly from rest to 23 m/s

u= 0m/s

v= 23m/s

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Step two:

We know that

acceleration= velocity/time

also,

velocity= distance/time

23= 30/t

t= 30/23

t= 1.30 seconds

hence

acceleration= 23/1.30

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2 years ago
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user100 [1]

Answer:

The answer is A.

Explanation:

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Water is completely filling black metallic vessel having cubic form and thin walls. The mass of water is 1 kg and initial temper
Brilliant_brown [7]

Answer:

Check the attached image

Explanation:

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A 65.8-kg person throws a 0.0413 kg snowball forward with a ground speed of 32.5 m/s. A second person, with a mass of 58.7 kg, c
guapka [62]

Answer:

v_{1} = 2.490\,\frac{m}{s}

v_{2} = 0.023\,\frac{m}{s}

Explanation:

The statement is described physically by means of the Principle of Momentum Conservation. Let assume that first person moves in the positive direction:

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(65.8\,kg)\cdot (2.51\,\frac{m}{s}) = (65.8\,kg)\cdot v_{1} + (0.0413\,kg)\cdot (32.5\,\frac{m}{s} )

Second Person

(0.0413\,kg)\cdot (32.5\,\frac{m}{s})+(58.7\,kg)\cdot (0\,\frac{m}{s})=(0.0413\,kg+58.7\,kg)\cdot v_{2}

The final velocities of the two people after the snowball is exchanged is:

v_{1} = 2.490\,\frac{m}{s}

v_{2} = 0.023\,\frac{m}{s}

6 0
3 years ago
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