All categories

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !! 100 POINTS IF YOU KNOW CHEMISTRY OR BIOLOGY

Chemistry

2 answers:

lys-0071 [83]3 years ago

5 0

I am 100% positive it is C. Have a ice day ( ^ω^ )

labwork [276]3 years ago

4 0

Answer:

SEE THE ABOVE IMAGE FOR ANSWER.

You might be interested in

Question 2/8<br> From left to right across the second period of the periodic table,

Norma-Jean [14]

Answer:

Explanation:

HE is a noble gas

6 0

3 years ago

The element iridium exists in nature as two isotopes: 191Ir has a mass of 190.9606 u, and 193Ir has a mass of 192.9629 u. The av

nlexa [21]

<u>Answer:</u> The percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope be 'x'. So, fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope will be '1 - x'

<u>For $_{77}^{191}\textrm{Ir}$ isotope:</u>

Mass of $_{77}^{191}\textrm{Ir}$ isotope = 190.9606 amu

Fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope = x

<u>For $_{77}^{193}\textrm{Ir}$ isotope:</u>

Mass of $_{77}^{193}\textrm{Ir}$ isotope = 192.9629 amu

Fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope = 1 - x

Average atomic mass of iridium = 192.22 amu

Putting values in equation 1, we get:

$192.22=[(190.9606\times x)+(192.9629\times (1-x))]\\\\x=0.3710$

Percentage abundance of $_{77}^{191}\textrm{Ir}$ isotope = $0.3710\times 100=37.10\%$

Percentage abundance of $_{77}^{193}\textrm{Ir}$ isotope = $(1-0.3710)=0.6290\times 100=62.90\%$

Hence, the percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

8 0

3 years ago

What controls the volumes of water in each cylinder once equilibrium is established?

Neporo4naja [7]

The increase in volume shift the equilibrium towards making more moles of gas, decrease in volume shift the equilibrium towards producing fewer moles of gas.

<h3>What is equilibrium?</h3>

The equilibrium of the gas is based on the pressure of the gas. With the increase in pressure, the equilibrium moves towards making fewer molecules of gas.

The gas equilibrium is proportional to the equilibrium K.

Increase in volume shift the equilibrium towards making more moles of gas, decrease in volume shift the equilibrium towards producing fewer moles of gas.

Learn more about equilibrium

brainly.com/question/13463225

#SPJ1

6 0

2 years ago

How many molecules in 4.10 mol H2O?

Shtirlitz [24]

Answer:

2,47 * $10^{24}$ (molecules)