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Romashka [77]
3 years ago
10

If a chemist has 2.3 moles of arsenic that has a molar mass of 74.92g/mol, which would be the best way to find out how many atom

s of arsenic are in the sample?
Multiply 2.3 bu the molar mass of arsenic.

Divide 2.3 by the molar mass of arsenic.

Multiply 2.3 by Avogadro's number.

Divide 2.3 by Avogadro's number.
Chemistry
2 answers:
Firlakuza [10]3 years ago
6 0
<h3>Answer:</h3>

              Multiply 2.3 by Avogadro's Number

<h3>Explanation:</h3>

                     As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (Atoms) contained by 2.3 moles of Arsenic (As), we will use following relation,

           Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹

Solving for Number of Molecules,

           Number of Atoms  =  Moles × 6.022 × 10²³ Atoms.mol⁻¹ **

(**<u><em>This is your answer</em></u>)

Putting values,

           Number of Atoms  =  2.3 mol × 6.022 × 10²³ Atoms.mol⁻¹

           Number of Atoms  =  1.38 × 10²⁴ Atoms

Hence,

           There are 1.38 × 10²⁴ Atoms present in 2.3 moles of Arsenic.

scZoUnD [109]3 years ago
4 0
Mulitply 2.3 by avogadros #
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Mazyrski [523]
The gram-formula mass of Sm is 150.36 u, and the gram-formula mass of O is 15.999 u, so the gram-formula mass of SmO is about 150.36+15.999 = 160.36 g/mol.

So, there are about (9.30 * 10^-3)(160.36)=1.49 grams
4 0
2 years ago
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Zarrin [17]

Answer:

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6 0
3 years ago
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Which of the following is a possible set of quantum numbers for an electron?
Luba_88 [7]
The phrasing of this exercise means that we have to exclude 3 out of the 4 choices.
We have that the 4 quantum numbers that an electron has are the defining numbers of that electron. The first coordinate, the principal quantum number ncan take any positive value since it defines the shell in which that electron is.

The second number is called the orbital angular momentum number and takes the values from 0 to n-1 (the integer ones) where n is the principal number. Hence, we can disqualify options 1 and 4; the 1st because the principal and the orbital number are the same which is not possible and the 4th because the orbital number is negative which is not possible.

The third is the magnetic quantum number and takes values from -l to l (all integer values in between). Hence, it cannot be equal to n again, so option 2 is disqualified too.
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P.S.
We have a 4th number, the spin number; this number can assume only the values +1/2 and -1/2
6 0
3 years ago
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const2013 [10]

Answer:

FLUORINE, CHLORINE, BROMINE, IODINE, ASTATILE AND TENNESINE

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HOPE IT is right

5 0
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Answer:

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Explanation:

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5 0
3 years ago
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