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Romashka [77]
3 years ago
10

If a chemist has 2.3 moles of arsenic that has a molar mass of 74.92g/mol, which would be the best way to find out how many atom

s of arsenic are in the sample?
Multiply 2.3 bu the molar mass of arsenic.

Divide 2.3 by the molar mass of arsenic.

Multiply 2.3 by Avogadro's number.

Divide 2.3 by Avogadro's number.
Chemistry
2 answers:
Firlakuza [10]3 years ago
6 0
<h3>Answer:</h3>

              Multiply 2.3 by Avogadro's Number

<h3>Explanation:</h3>

                     As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (Atoms) contained by 2.3 moles of Arsenic (As), we will use following relation,

           Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹

Solving for Number of Molecules,

           Number of Atoms  =  Moles × 6.022 × 10²³ Atoms.mol⁻¹ **

(**<u><em>This is your answer</em></u>)

Putting values,

           Number of Atoms  =  2.3 mol × 6.022 × 10²³ Atoms.mol⁻¹

           Number of Atoms  =  1.38 × 10²⁴ Atoms

Hence,

           There are 1.38 × 10²⁴ Atoms present in 2.3 moles of Arsenic.

scZoUnD [109]3 years ago
4 0
Mulitply 2.3 by avogadros #
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3 years ago
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
nikklg [1K]

Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

                     x = 0.953

So, the quality of the wet steam is 0.953

                   

7 0
3 years ago
Read 2 more answers
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