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Answer is
C. 2.07 M
For explanation
M1V1 = M2V2
M2 = (M1V1)/V2
M2 = (1.5M x 345ml) / 250 ml
:. M2 = 2.07 M
The interaction between the substances and stomata is a chemical reaction, light energy strikes at the chlorophyll molecules, whose electrons gets excited to a state of higher energy, and they come back to their state of lower energy by emission of energy, which is accepted by a chain of acceptors, and energy is generated.
Answer:
0.474 moles of C₆H₆OS
Explanation:
Step 1: Write the balanced equation
2 C₆H₆OS + 11 O₂ ⇒ 12 CO + 6 H₂O + 2 SO₃
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of C₆H₆OS to SO₃ is 2:2.
Step 3: Calculate the moles of C₆H₆OS reacted if 0.474 moles of SO₃ are produced
We will use the previously established molar ratio.
0.474 mol SO₃ × 2 mol C₆H₆OS/2 mol SO₃ = 0.474 mol C₆H₆OS
Answer:
5.36 moles
Explanation:
From the given chemical equation, we see that one mole of nitrogen gas reacts with 3 moles of hydrogen gas in terms of mass.
Molar mass of hydrogen gas ; H2 = 2.016 g/mol
Molar mass of nitrogen gas; N2 = 28.01 g/mol
Thus;
28.01 grams of nitrogen gas requires 3 moles of hydrogen gas
Thus;
28.01 grams of nitrogen gas requires 3 moles of hydrogen gas
Therefore, 50 g of nitrogen gas will require; (50 × 3)/28.01 = 5.36 moles