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BigorU [14]
3 years ago
9

when holly injures her shoulder she uses an ice pack. she activates the ice pack releasing the urea. what process does she obser

ve as she uses the cold pack?
Chemistry
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

Holly observes that the ice pack becomes colder when she activates it.

Explanation:

She infers that the process of the urea dissolving in water is endothermic.

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In a chemical reaction, the atoms and molecules that interact with each other are called reactants. ... No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.
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What is the heat of vaporization of ethanol, given that ethanol has a normal boiling point of 63.5°C and the vapor pressure of e
Serjik [45]

Explanation:

According to Clausius-Claperyon equation,

       ln (\frac{P_{2}}{P_{1}}) = \frac{-\text{heat of vaporization}}{R} \times [\frac{1}{T_{2}} - \frac{1}{T_{1}}]

The given data is as follows.

         T_{1} = 63.5^{o}C = (63.5 + 273) K

                         = 336.6 K

        T_{2} = 78^{o}C = (78 + 273) K

                         = 351 K

         P_{1} = 1 atm,             P_{2} = ?

Putting the given values into the above equation as follows.    

        ln (\frac{P_{2}}{P_{1}}) = \frac{-\text{heat of vaporization}}{R} \times [\frac{1}{T_{2}} - \frac{1}{T_{1}}]

       ln (\frac{1.75 atm}{1 atm}) = \frac{-\text{heat of vaporization}}{8.314 J/mol K} \times [\frac{1}{351 K} - \frac{1}{336.6 K}]

                      \Delta H = \frac{0.559}{1.466 \times 10^{-4}} J/mol

                                  = 0.38131 \times 10^{4} J/mol

                                  = 3813.1 J/mol

Thus, we can conclude that the heat of vaporization of ethanol is 3813.1 J/mol.

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Answer:

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