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AlekseyPX
3 years ago
11

What is the scale factor of each model?

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0

Answer:

5 inches

-I really tried

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The diameter of a human red blood cell is 0.000009 m The diameter of a cold virus is 0.00000003 m. Approximately how many times
Lera25 [3.4K]

Answer:

Red Cell is 300 times larger than the virus

Step-by-step explanation:

Size in scientific Notation

  • Red Cell = 9 * 10^-6
  • Virus = 9 * 10^-8

Procedure.

  • Count the number of zeros in the decimal
  • Red Cell = 5 ; virus = 7
  • And one more to each
  • Red Cell = 6; virus = 7
  • change the numbers to minus
  • Red Cell = -6 ; virus = - 7
  • The last row is the powers as shown above.

Answer

9*10^-6/3 * 10^-8

3*10^(-6 - - 8)

3*10^(-  6 + 8)

3^10^2 or 300 times larger

4 0
2 years ago
Read 2 more answers
Complete the square on the following quadratic x2+10x+9=0
kakasveta [241]
Given a quadratic equation x^{2} +ax+c=0

1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.

In our case the coefficient of x is 10, so we write 10 as 2*5

2. then we write + 5^{2} and - 5^{2} to the expression:

x^{2} +2*5*x+ 5^{2} -5^{2}+9=0

(x^{2} +2*5*x+ 5^{2}) -25+9=0

(x+5)^{2}-16=0



Answer: (x+5)^{2}-16=0
8 0
3 years ago
PLEASE HELP!!! TRIG, Theres a picture!!
BartSMP [9]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

3(  { \tan }^{2} \theta -    { \sec }^{2}  \theta)

Using trigonometric identities

That's

1 + { \tan }^{2} \theta  =   { \sec }^{2}  \theta

Rewrite the expression

That's

3({ \tan }^{2} \theta - (1 + { \tan }^{2} \theta)) \\

Simplify

We have

3({ \tan }^{2} \theta - 1 - { \tan }^{2} \theta) \\ 3({ \tan }^{2} \theta - { \tan }^{2} \theta - 1)

So we have

3( - 1)

We have the final answer as

<h2>- 3</h2>

Hope this helps you

3 0
3 years ago
What is another name for ray AE ?
zlopas [31]

Answer:

EA

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Your next math test is worth 111 points and contains 32 problems. Each problem is worth either 4 points or 3 points. How many 3
Dafna11 [192]
We call x the 4 points-worth problems and y the 3 points-worth problems

You know that x+y = 32

4x+3y = 111

You know that the difference from the x and y is 32 so write:

x = 32-y

Substitute at x the value of 32-y

4(32-y)+3y = 111

128-4y +3y = 111

-4y+3y = 111-128

-y = -17

y = 17
3 0
2 years ago
Read 2 more answers
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