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Assoli18 [71]
3 years ago
11

;Select all that apply. which of these polygons is not formed by the cross-section created when a plane intersects a cube? selec

t all that are possible. -square -circle -pentagon -trapezoid -triangle -rectangle
Mathematics
2 answers:
Reil [10]3 years ago
7 0
Square, circle, or rectangle
MariettaO [177]3 years ago
6 0

Answer:

The answer is circle.

Step-by-step explanation:

When a cube is intersected by a plane parallel to its base, a square is created. A rectangle is created when a cube is intersected by a plane in 2 pairs of opposite faces. When a cube is intersected by a plane in 3 adjacent faces, a triangle is formed.

Since a cube does not have any curved faces, so a plane will not be able to intersect it and give a cross section with any curves.

So, a circle is not possible.

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If m<1 = 7x-19 and m<2 = x+5 find m<2
lbvjy [14]

Answer:55

Step-by-step explanation:

55

7 0
3 years ago
If you could help I would really appreciate it, but if not that’s fine. Thank you.
zloy xaker [14]

Answer:

2x - 5 if x ≤ 2

f(-1) = -7

Step-by-step explanation:

x ≤ 2 = (-1) ≤ 2

x > 2 = (-1) > 2

2x - 5

2(-1) - 5

-2 - 5

-7

8 0
3 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Can you please help me with the question the link is down below
Shkiper50 [21]

Answer:

output = 9

Step-by-step explanation:

add 5 to the input to obtain output

output = 4 + 5 = 9

7 0
2 years ago
Ray is reading a book of 150 pages at a constant rate of 25 pages per hour. Let’s consider the following function: the pages lef
sineoko [7]

Question:

     R U CONSTIPATED?

4 0
3 years ago
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