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3 years ago

Please let me know I really need help

Mathematics

1 answer:

Marina86 [1]3 years ago

5 0

I don't have a calculator with me, but that should get you going

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Note that 3 is a factor of 21. This means that 3×[]=21. Another way to write this is 3×n=21. Find a value of n that makes the st

mash [69]

Answer:

n=9

Step-by-step explanation:

$3*9=21$

7 0

2 years ago

Kendra sold 200 shares through her broker on June 8. The price per share was $22.10. The broker charged her a 0.5% commission on

KiRa [710]

Answer:

A. $4397.9

Explanation:

We are given that Kendra sold 200 shares and that the price per share was $22.1

This means that:

Total value = 200 * 22.1 = $4420

Now, we know that the broker charged 0.5% commission on the total value

This means that:

Broker's charge = 0.5% * 4420 = 0.005 * 4420 = $22.1

Therefore,

Kendra's return = Total value - broker's charge

Kendra's return = 4420 - 22.1 = $4397.9

Hope this helps :)

7 0

2 years ago

Which ordered pair describes a point that is located 1 unit to the left of the origin and 3 units above the x-axis?

goldfiish [28.3K]

Answer:

Cartesian plane

Step-by-step explanation:

(–1 , 3)

4 0

2 years ago

Read 2 more answers

What is the value of x? 6x−1=4x−5

ch4aika [34]

X=-2
Explanation is I just know the answer

8 0

2 years ago

Read 2 more answers

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

2 years ago