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sladkih [1.3K]
3 years ago
5

I thought I had $35 in my bank account.

Mathematics
1 answer:
dexar [7]3 years ago
6 0

your awnser will be 100 because if

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First responder in under 2 minutes gets brainly
katrin [286]

Answer:

C

Step-by-step explanation:

The x's can not completely cancel each other out so they are still included but you have to divide the numbers, exponents and whole numbers.

6 0
3 years ago
Read 2 more answers
Help me with this questing plsss
docker41 [41]

Answer:

6.25n + 3.50

$34.75

Step-by-step explanation:

Break down the important information given in the problem.

The one-time delivery fee is 3.50. This is only paid one time an never again, making it the <u>constant</u>, a number that does not change.

Each lunch costs 6.25. This amount will increase depending on how many times Mr. Jackson orders lunches, "n" times. This number is the <u>rate</u> because it changes. The rate is attached to the variable.

If you add the amounts together, that is the total cost of ordering lunches.

6.25n + 3.50

(Reember expressions do not have the equal sign).

To find the cost of ordering 5 lunches, use the expression. Substitute "n" for 5 because "n" represents the number of lunches ordered.

6.25n + 3.50

= 6.25(5) + 3.50   Simplify by multiplying 5 and 6.25

= 31.25 + 3.50    Add the two values

= 34.75       Total cost of 5 lunches

Therefore the cost of ordering 5 lunches is $34.75.

8 0
3 years ago
A boy's mother was 32 years old when he was born. Let a represent the boy's age and m represent the mother's age.
LenKa [72]

see the picture attached

5 0
2 years ago
I need help on this asap please.
artcher [175]

Answer:

way to hard sorry cant help you

8 0
3 years ago
The ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years. Approxima
worty [1.4K]

We have been given that the ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years.

We are asked to find the percentage of students that are between 14 and 18 years old.

First of all, we will find z-score corresponding to 14 and 18 using z-score formula.

z=\frac{x-\mu}{\sigma}

z=\frac{14-15}{2}

z=\frac{-1}{2}

z=-0.5

Similarly, we will find the z-score corresponding to 18.

z=\frac{18-15}{2}

z=\frac{3}{2}

z=1.5

Now we will find the probability of getting a z-score between -0.5 and 1.5 that is P(-0.5.

P(-0.5

Using normal distribution table, we will get:

P(-0.5

P(-0.5

Let us convert 0.62465 into percentage.

0.62465\times 100\%=62.465\%\approx 62.5\%

Therefore, approximately 62.5\% of the students are between 14 and 18 years old.

8 0
3 years ago
Read 2 more answers
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