The question is incomplete. The complete question is :
The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?
Solution :
According to the question,
The rate of change of population is given as :
in 1990.
Now integrating,

![$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B200%7D%7B0.02%7D%5Cleft%5Be%5E%7B0.02%2820%29%7D-1%5Cright%5D%24)
![$=10,000[e^{0.4}-1]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5Be%5E%7B0.4%7D-1%5D%24)
![$=10,000[0.49]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5B0.49%5D%24)
=4900





This is initial population.
k is change in population.
So in 1995,



In 2000,


Therefore, the change in the population between 1995 and 2000 = 1,163.
Answer:
c
Step-by-step explanation:
Given that, a sphere has a surface area of about 999 square millimeters.
Formula to find the surface area of sphere is,
S= 4πr² Where r = radius of the sphere and S= surface area.
Given S= 999 square millimeters.
So, we can write:
4πr² = 999
4 * 3.14 * r² = 999 Since, π = 3.14
12.56 *r² = 999
Divide each sides by 12.56.
r² = 79.53821656
r = √79.53821656 Taking square root to each sides of equation.
r = 8.918420071
So, r = 8.918 Rounded to nearest thousandth.
So, radius of the sphere is 8.918 millimeters.
Hope this helps you!
Answer:
i don't know
Step-by-step explanation:
sorry
<4 and <2 corresponding angles
<6 and <3 alternate interior angles
<4 and <5 alternate exterior angles
<6 and <7 interior angles on the same side of transversal