Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
, 
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Answer:
solution
Step-by-step explanation:
I don’t know what the equation is but when using elimination you should cancel out opposite numbers such as 4x and negative 4x
We have that
A(-4,-4) B(-2,5) C(2,1) D(2,-4)
step 1
find the distance AC with the formula
d=√[(y2-y1)²+(x2-x1)²]------> dAC=√[(1+4)²+(2+4)²]----> dAC=√61 units
dAC=√61-----> dAC=7.8 units
the answer is
the option
<span>B. 7.8 units</span>
