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3 years ago

Noah's oven thermometer gives a reading that is 2% more than the actual temperature.

Mathematics

1 answer:

Korvikt [17]3 years ago

8 0

2 percent more means that you take 102 percent of the actual reading, 102 percent of 325= 331.5 degrees

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One cup is equal to 14.4375 in^3. If a 1-cup measuring cylinder has a radius of 3 in., what is its height? If

patriot [66]

Answer:

The height of the cup is 0.51 in.

The height of the cup is 4.59 in.

Step-by-step explanation:

The volume of the cylinder is $\pi r^2 h$

Given that,

The volume of the cup is 14.4375 in³.

If the measuring cup has a radius of 3 in.

Then,

$\pi r^2h=14.4375$

Plug r= 3 in.

$\pi (3)^2h=14.4375$

$\Rightarrow h=\frac{14.475}{9\pi }$

⇒h=0.51 in.

The height of the cup is 0.51 in.

If it has radius of 1 in.

Then,

$\pi r^2h=14.4375$

Plug r= 1 in.

$\pi (1)^2h=14.4375$

$\Rightarrow h=\frac{14.475}{1\pi }$

⇒h=4.59 in.

The height of the cup is 4.59 in.

3 0

3 years ago

K-2k=15+1+6k-2 help me

sveticcg [70]

K - 2k = 15 + 1 + 6k - 2

-k = (15 + 1 - 2) + 6k

-k = 14 + 6k |subtract 6k from both sides

-7k = 14 |divide both sides by (-7)

k = -2

6 0

3 years ago

What is 170 as a decimal (in the hundreths)

Rufina [12.5K]

It would be 1.70

Hope this helps!

6 0

3 years ago

In order to get promoted to the next grade, a student is required to score above 55 in the final test. Assume the scores to be n

murzikaleks [220]

Answer:

$P(X>55)=P(\frac{X-\mu}{\sigma}>\frac{55-\mu}{\sigma})=P(Z>\frac{55-60}{5.5})=P(z>-0.909)$

And we can find this probability with the complement rule:

$P(z>-0.909)=1-P(z$

And we can use excel or the normal standard table and we got:

$P(z>-0.909)=1-P(z$

So then we expect about 81.8% of students that will be promoted

Step-by-step explanation:

Let X the random variable that represent the scores of promotion of a population, and for this case we know the distribution for X is given by:

$X \sim N(60,5.5)$

Where $\mu=60$ and $\sigma=5.5$

We want to find the following probability:

$P(X>55)$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

Using the z score formula we got:

$P(X>55)=P(\frac{X-\mu}{\sigma}>\frac{55-\mu}{\sigma})=P(Z>\frac{55-60}{5.5})=P(z>-0.909)$

And we can find this probability with the complement rule:

$P(z>-0.909)=1-P(z$

And we can use excel or the normal standard table and we got:

$P(z>-0.909)=1-P(z$

So then we expect about 81.8% of students that will be promoted

7 0

4 years ago

I need help finding the mean, median, mode, and range of 32, 48, and 22

nataly862011 [7]

Mean=34 Mode=none Median=32 Range=26

6 0

3 years ago

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