3 years ago

K-2k=15+1+6k-2 help me

1 answer:

6 0

K - 2k = 15 + 1 + 6k - 2

-k = (15 + 1 - 2) + 6k

-k = 14 + 6k |subtract 6k from both sides

-7k = 14 |divide both sides by (-7)

k = -2

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Vika [28.1K]

-1299 hope it's good enough

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3 years ago

vovikov84 [41]

Plug $y=x^2$ into the equation of the ellipsoid:

$x^2+7(x^2)^2+7z^2=49$

Complete the square:

$7x^4+x^2=7\left(x^4+\dfrac{x^2}7+\dfrac1{14^2}-\dfrac1{14^2}\right)=7\left(x^2+\dfrac1{14}\right)^2+\dfrac1{28}$

Then the intersection is such that

$7\left(x^2+\dfrac1{14}\right)^2+7z^2=\dfrac{1371}{28}$

$\left(x^2+\dfrac1{14}\right)^2+z^2=\dfrac{1371}{196}$

which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let

$x(t)^2+\dfrac1{14}=\sqrt{\dfrac{1371}{196}}\cos t\implies x(t)=\pm\sqrt{\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}}$

$y(t)=x(t)^2=\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}$

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(Attached is a plot of the two surfaces and the intersection; red for the positive root $x(t)$ , blue for the negative)

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3 years ago

lutik1710 [3]

Answer:

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Step-by-step explanation:

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vova2212 [387]

I’m doing algebra too and I’m stuck!!!

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almond37 [142]

((4x+15)/(5x)) = 1/2
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