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Sedaia [141]
3 years ago
7

Please Find the solution to the following system using substitution or elimination: y = 3x + 7 y = -2x -3

Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0
Answer: A (-2, 1)
see image explanation attached

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The formula for the future value V (in dollars) of an investment earning simple interest is V=p+prt, where p (in dollars) is the
zhannawk [14.2K]

a)

V=p+prt

now we solve for P

V=P (1+rt)

Divide both sides by (1+rt)

P=V÷(1+rt)...answer

b)

P=V÷(1+rt)

P=3,000÷(1+0.06×5)

P=2,307.69

5 0
3 years ago
How was life different for Romans with low incomes and wealthy Romans? Romans living in poverty had few duties and more free tim
ahrayia [7]

Wealthy Romans relied on servants to run their households.

brainly.com/question/16395373

8 0
2 years ago
F(x)= x squared -3x + 2 divided by 3x squared + 9 x -12
VashaNatasha [74]

Answer:

=(x-2)/3(x+4)

Step-by-step explanation:

F(x)=x²-3x+2/3x²+9x-12

Using mid term break formula

=x²-2x-x+2/3(x²+3x-4)

=x(x-2)-1(x-2)/3(x²+4x-x-4)

=(x-2)(x-1)/3{x(x+4)-1(x+4)}

=(x-2)(x-1)/3(x-1)(x+4)

Cancelling (x-1)

We get

=(x-2)/3(x+4)

Hope it helps :)

6 0
3 years ago
The diameter of a circle is 17 cm. Find the circumference \textit{to the nearest tenth}to the nearest tenth.
aev [14]

Answer:

52.4 cm

Step-by-step explanation:

Circumference of a circle = 2πr

Radius, r = diameter / 2

= 17 cm / 2

= 8.5 cm

π = 3.14

Circumference of a circle = 2πr

= 2 × 3.14 × 8.5

= 53.38 cm

Approximately 52.4 cm

5 0
2 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
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