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OleMash [197]
3 years ago
11

What is the degree of the polynomial?

Mathematics
1 answer:
saw5 [17]3 years ago
7 0
Ddddddddddddddddddddddddddddddddddddddd
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Click on the solution set graphic until the correct one is displayed.
zalisa [80]

Answer:

  (b) (infinite set of points on the line)

Step-by-step explanation:

The graph appears to show two coincident lines. The points they have in common is the solution set to the pair of equations they represent:

  (infinite set of points on the line)

4 0
3 years ago
A bank is experimenting with programs to direct bill companies for commercial loans. They are particularly interested in the num
Evgesh-ka [11]

Answer:

The 95% confidence interval for true mean error is (4.57, 4.63).

Step-by-step explanation:

Let <em>X</em> = the number of errors of a billing program.

According to the Central limit theorem if a large sample (<em>n</em> > 30) is drawn from an unknown population then the sampling distribution of the sample mean will follow a Normal distribution with mean (\mu_{\bar x}=\mu) and standard deviation      (\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}).

The sample size of the loans is, <em>n</em> = 1000.

The mean is, {\bar x}=4.6.

The standard deviation is,  \sigma_{\bar x}=\frac{0.50}{\sqrt{1000}}=0.016

The confidence interval for mean is:

CI=\bar x\pm z_{\alpha /2}\times \sigma_{\bar x}

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha /2}=z_{0.05/2}=z_{0.025}=1.96

**Use the <em>z</em>-table for critical values.

Compute the 95% confidence interval for true mean error as follows:

CI=\bar x\pm z_{\alpha /2}\times \sigma_{\bar x}\\=4.6\pm1.96\times0.016\\=4.6\pm0.03136\\=(4.56864, 4.63136)\\\approx(4.57, 4.63)

Thus, the 95% confidence interval for true mean error is (4.57, 4.63).

7 0
3 years ago
Read 2 more answers
What is m
Lemur [1.5K]

Answer

m=40/63

Step-by-step explanation:

if you want to simpliyfiy its 0.635

7 0
3 years ago
Read 2 more answers
You says on the picture
elena-s [515]
Use the Pythagorean Theorem. a^2+ b^2=c^2.
In this case, it is c^2-b^2=a^2, so your answer is 4.686 mm^2. Round if you need to.
4 0
4 years ago
Read 2 more answers
Wesley Estimated 5.82-4.21 to be about 2. Is this an overestimate or an underestimate?
Bezzdna [24]
I'd say neither because 5.82-4.21 equals to 1.61, and it does not go above 2 as an overestimate. In addition, it's not an underestimate because 1.61 rounds up to 2. If you can't put that as an answer, you can say its an underestimate because it does not meet the real standards of being 2.
8 0
3 years ago
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