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3 years ago

9

Please help ASAP failing class if i dont answer correct

1 answer:

NNADVOKAT [17]3 years ago

8 0

(See the imagine for reference)
Let’s solve where they have a triangle, so the height is 9 cm, the base is 3 cm:

1/2 • 9 • 3 = 13.5

Since there’s 2 triangles we do:

13.5(2) = 27

Now the rectangle in the middle, where the height is 9cm and the base is 12cm:

12 • 9 = 108

Add up the areas:

108 + 27 = 135

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3 years ago

Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If BC=10BC=10 and DC=5,DC=5, what is the le

Helen [10]

Answer: $\overline{AC}=$ 12.5

Step-by-step explanation: The triangle ABC and its altitude $\overline{BD}$ is represented in the figure below.

<u>Altitude</u> is a segment of line that link a vertex and the opposite side, forming a right angle.

So, because of $\overline{BD}$ , now we have two similar triangles, which means that ratios of corresponding sides are equal:

$\frac{\overline{BD}}{\overline{BC}} =\frac{\overline{AD}}{\overline{BD}}$

$\overline{BD}^{2}=\overline{BC}.\overline{AD}$ (1)

This is always true for a right triangle and a altitude drawn to the hypotenuse.

Triangle BDC is also right triangle. So, we can use Pythagorean theorem to determine the missing side.

$\overline{BC}^{2}=\overline{CD}^{2}+\overline{BD}^{2}$

$\overline{BD}^{2}=\overline{BC}^{2}-\overline{CD}^{2}$ (2)

Substituting (2) into (1):

$\overline{BC}^{2}-\overline{CD}^{2}=\overline{BC}.\overline{AD}$

We want to find f, so:

$\overline{AD}=\frac{\overline{BC}^{2}-\overline{CD}^{2}}{\overline{BC}}$

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The length of $\overline{AC}$ is

$\overline{AC}=f+5$

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The length of the hypotenuse of triangle ABC is 12.5 units.

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