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alekssr [168]
3 years ago
10

If you wanted to find the mean height of students in an elementary school,

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

It is not possible to select a single group from the primary school, since being a single group it could not in any way represent the entire primary school.

Choosing a group would provide the average height for that group, not the entire primary.

Assumptions can be made that the course of half of the primary would theoretically give us a more accurate representation, but the objective is to select a number of students from each course and there would be a representative sample of the entire primary.

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Answer:

Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$

Step-by-step explanation:

8 0
3 years ago
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