Answer:
The null hypothesis would be
H0: μ1=μ2=μ3 (all the means of the three sites are equal)
Step-by-step explanation:
Site I Site II Site III
28 47 46
54 22 27
44 65 40
16 56 22
21 17 58
36
The null hypothesis would be
H0: μ1=μ2=μ3 (all the means of the three sites are equal) against the claim
Ha: μ1≠μ2≠μ3 (all the means of the three sites are not equal)
Which if H0 is true, has an F -distribution with v1=k-1 and v2= n-k degrees of freedom.
ANOVA (one way of analysis of variance ) can be applied to test this hypothesis.
