Help from 1-3 plz!!!

kogti [31]

9/10 - 2/5 + 1/3

= 5/6 (Decimal: 0.8333333)

Subtract:
9/10 - 2/5 = 9/10 - 2 . 2/5 . 2
= 9/10 - 4/10
= 9 - 4/10
= 5/10
= 1/2

The common denominator you can calculate as the least common multiple of the both denominators LCM ( 10, 5) = 10

Add: 1/2 + 1/3 = 1 . 3/2 . 3 + 1 . 2/3 . 2
= 3/6 + 2/6
= 3 + 2/6

= 5/6

The common denominator you can calculate as the least common multiple of the both denominators LCM ( 2, 3) = 6

Answer in Lowest term is: 5/6 or Decimal: 0.8333333

Hope that helps!!!

7 0

3 years ago

Which statement is true about the given function? f(x) < 0 over the intervals (–infinity, –2.7) and (0.8, infinity). f(x) &lt

Lesechka [4]

Answer: f(x) < 0 over the intervals (–infinity, –2.7) and

(–1, 0.8).

Step-by-step explanation:

I got it right

8 0

3 years ago

Read 2 more answers

Please help me out :/

tensa zangetsu [6.8K]

Add up all of your X’s!! then Try and add up all of the degrees I think. Check me if i’m wrong !

7 0

2 years ago

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

Read 2 more answers

What is an equation of the line that is parallel to y=3x-8 and passes through the point, (4,-5)

VladimirAG [237]

Answer:

y= 3x-17

Step-by-step explanation:

When finding a parallel equation to y=mx+b, mx will always stay the same. So we have to find b.

In order to do this you plug the parallel lines passing point into the equation.

-5(y) goes into the y's spot. 4(x) goes into the x's spot.

-5 = 3 x 4 + b

-5 = 12 + b

-5 - 12 = 12 - 12 + b

-17 = b

y=3x-17

5 0

2 years ago