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Solnce55 [7]
3 years ago
14

the number cubes the Fifth grade math classes use are packed into a box. when the box is full, it has 5 rows of 4 cubes with 6 l

ayers of cubes. Mrs. Benson sees that one layer of cubes is missing from the box. how many number cubes are in the box? (a) 96 (b) 100 (c) 90 or (d) 50
Mathematics
2 answers:
densk [106]3 years ago
8 0
4x5=20. 20x6=120. 120-20=100 b)100
BigorU [14]3 years ago
5 0
5 rows of 4 cubes will be 20 cubes per row. with 6 layers that will be 6x20 which is 120. minus a row of 20 would be (b) 100
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(9) power 3 +(3) power 2+(6) power 3+(15)power 2=?
Kisachek [45]
Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!


So-------

9^3=729

3^2=9

6^3=216

15^2=225



Now that we have that figured out, we can add them together, wish is simple. 729 + 9 + 216 + 225= 1,179.



Therefore, your final answer will be 1,174.




If you have any questions on this, I'm happy to help you. :)
5 0
3 years ago
`PLSS PLSSS HELPPP I WILL GIVE BRAINLIESTTTT!!!!!!!
lidiya [134]

Answer:

ASA i think

Step-by-step explanation:

because if you start anywhere on the triangle you start at an angle

5 0
3 years ago
What’s the value of X ? PLS HELP )):
motikmotik

Answer:

By angle sum property,

56 + 92 = 148

180 - 148 = 32

linear pair

so ,  180 - 32

= 148

Hope it helps

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Thank you

6 0
3 years ago
Which of these expressions CANNOT be simplified by combining like terms?
densk [106]
5ab^{3} +7-3a^{2} b ^{2} +a^{3}b+10 can be simplified to by adding the 7 and 10 to get a^{3}b-3a^{2} b ^{2}+ 5ab^{3} + 17.

5ab^{3}+3a^{2}b^{2}+a^{3}b -10 cannot be simplified any more by combining like terms.

By distributing the 2b into the parentheses, you can simplify the expression:
5ab^{3}+2b(3ab^{2})+a^{3}b-10\\
5ab^{3}+6ab^{3}+a^{3}b-10\\
11ab^{3}+a^{3}b-10

Here you can just add:
5a^{3}b^{3}+3a^{2}b^{2}+a^{3}b^{3}-10ab\\
6a^{3}b^{3}+3a^{2}b^{2}-10ab

Thus, the only expression that cannot simplify any more using adding like terms is the second, 5ab^{3}+3a^{2}b^{2}+a^{3}b -10.
3 0
3 years ago
Read 2 more answers
If Angle 8 is congruent to angle 10 and Angle 1 is congruent to angle 7, which describes all the lines that must be parallel?
Misha Larkins [42]

Answer:  C is the correct answer Lines r and s and lines t and u must be parallel.

Step-by-step explanation: the step by step explanation is the the lines that answer C says are parallel

Lines r and s are crossed by lines t and u to form 16 angles. Clockwise from top left, at the intersection of r and t, the angles are 1, 2, 3, 4; at the intersection of s and t, 5, 6, 7, 8; at the intersection of u and s, 9, 10, 11, 12; at the intersection of u and r, 13, 14, 15, 16.

6 0
3 years ago
Read 2 more answers
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