Answer:
Range = (7,5,-1,-9)
Point 1 = ( -3, 7)
Point 2 = ( -2, 5)
Point 3 = ( 1, -1)
Point 4 = ( 5, -9)
Step-by-step explanation:
g(x)= 1-2x
The domain is x.
The range is y.
g(x) is the function.
To solve this you just input each number from the domain into the function.
g(x) = 1 - 2(-3)
-2 × -3 = positive 6
It is a positive because a negative multipled by a negative equals a positive. This means it is not 1-6 because it is not a negative, it would be 1+6.
1 + 6 = 7
g(x) = 1 -2(-2)
-2 × -2 = positive 4
1 + 4 = 5
g(x)= 1 - 2(1)
-2 × 1 = -2
Since it is multipled 1 time it will be -2. So the equation is still 1-2.
1 - 2 = -1
g(x)= 1 - 2(5)
-2 × 5= -10
A negative multipled by a positive is a negative.
1 - 10 = -9
Now that you have all the numbers put them in parentheses things like the domain
Range = {7,5,-1,-9}
To graph it you need to put in each point by finding the first number of the domain and range and that is your point.
The first point would be (-3,7) and so on and so forth.
Answer:
Step-by-step explanation:
Given,
Base of the triangle = 6
Hypotenuse of the triangle = 8
Let the height of the triangle = x
Therefore, According to Pythagoras Theorem,
Answer:
Polynom degree: 5
Y intercept point: (0, 80)
Step-by-step explanation:
P(x)=(x+5)(x+4)²(x+1)²
When you expand, the highest power of x is 1 for first term (x+5), 2 for second term (x+4)² and again 2 for (x+1)². Overall, x⁵ will be the x term with highest power. So the degree of the polynom is 5.
The y intercept, i.e. intersection with OY axis, happens for x=0. Thus, P(0)=5×4²×1²=5×16=80. The y intercept point is (0, 80)
Now what you want to do is 21 + (-3). Since this is the same as saying 21 - 3, the answer is 18. Therefore, the answer is 18°F.
Answer:
b1 = 2 ; r = 3
Step-by-step explanation:
Given that :
if b3 −b1 = 16 and b5 −b3 = 144.
For a geometric series :
Ist term = a
Second term = ar
3rd term = ar^2
4th term = ar^3
5th term = ar^4 ;...
If b3 - b1 = 16;
ar^2 - a = 16
a(r^2 - 1) = 16 - - - (1)
b5 - b3 = 144
ar^4 - ar^2 = 144
ar^2(r^2 - 1) = 144 - - - - (2)
Divide (1) by (2)
a(r^2 - 1) / ar^2(r^2 - 1) = 16 /144
a / ar^2 = 1 / 9
ar^2 = 9a
Substitute for a in ar^2 - a = 16
9a - a = 16
8a = 16
a = 2
From ar^2 - a = 16
2r^2 - 2 = 16
2r^2 = 16 + 2
2r^2 = 18
r^2 = 18 / 2
r^2 = 9
r = √9
r = 3
Hence ;
a = b1 = 2 ; r = 3
