Find the measure of x. a. 160 b. 100 c. 120 d. 80

UNO [17]

Answer:

The answer is 1

So first you will multiply the terms with the same base by adding their exponents. Then solve the exponents. Then the only thing you will have left is 7 to the power of 0. Which equals 1

4 0

3 years ago

What is the equation of a horizontal line passing through the point (−7, 5)? (1 point)

netineya [11]

If it’s a horizontal line, we focus on the y-coordinates.

(-7,5)

-7 is a x-coordinate
5 is a y-coordinate

The answer is y = 5

6 0

3 years ago

Geometry help needed, please?

soldi70 [24.7K]

Answer:

A quadrilateral has 4 right angles

Step-by-step explanation:

In a conditional statement

If hypothesis, then conclusion

OR

Conclusion, if hypothesis.

The hypothesis goes with the if part.

4 0

3 years ago

The combined area of a square and a rectangle is 225 square yards. the length of the rectangle is 8 times the width of the recta

snow_lady [41]

Answer:

The rectangle: L = 40 yards. W = 5 yards

The square: The length and width are both 5 yards.

Step-by-step explanation:

Let L and W be the length and width of the rectangle.

Let l and w be the length and width of the square.

Area for each is:

Rectangle: L*W

Square: l*w

We are told that L*W + l*w = 225 yards^2

We are also told that

L = 8W

and that

l = W

Since the sides of a square are all equal, w is also W: w=W

Summarizing and substituting:

L*W + l*w = 225 yards^2

(8W)*W + W*W = 225 yards^2

8W^2 + W^2 = 225 yards^2

9W^2 = 225 yards^2

W^2 = 25

W = 5 feet

---------------------

Therefore, since L = 8W , L = 40 yards. W = 5 yards for the rectangle.

The square: l=W, so l = 5 yards, and thus w=5 yards

--------------------------

Check:

Do a rectangle of 40' x 5' plus a square of 5' x 5' have a total combined area of 225 yards^2?

40yd x 5yd + 5yd x 5yd = 225 yards^2?

200 yd^2 + 25 yd^2 = 225 yards^2?

YES

5 0

2 years ago

A carpenter wants to build a rectangular box with square sides in which to put round things. the material for the bottom costs $

alexira [117]

Answer: $1.627\times 1.627\times 1.88\ ft^3$

Step-by-step explanation:

Given

Suppose side face have a dimension of l\times l

and width of h

volume $V=l^2\cdot h$

$h=\frac{V}{l^2}$

volume $V=5 ft^3$

Area of side wall is $A_s=l^2$

Area of top Wall $A_t=l\times h$

Area of bottom $A_b=l\times h$

Cost of bottom wall $c_b=20\times l\times h=20lh$

Cost of top wall $c_t=50\times l\times h=50lh$

Cost of side walls $c_s=4\times l^2\times 10=40l^2$

total cost $C=c_s+c_t+c_b=20lh+50lh+40l^2$

$C=70lh+40l^2$

$C=70\times l\times \frac{5}{l^2}+40l^2$

differentiate C w.r.t l to get minima or maxima

$\frac{\mathrm{d} C}{\mathrm{d} l}=0$

$-\frac{350}{l}+80l^2=0$

$l^3=\frac{350}{80}$

$l=1.627 ft$

$h=\frac{5}{2.648}$

$h=1.88 ft$

Dimension of Box is $1.627\times 1.627\times 1.88\ ft^3$

5 0

3 years ago