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3 years ago

Help me, it's easy ig

Mathematics

2 answers:

jenyasd209 [6]3 years ago

8 0

Answer:

Step-by-step explanation:

fill the black in with the number 12

mash [69]3 years ago

4 0

10

30 times 4 is 120 and 3 *4* 10 is also 120

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Please help me solve this,

tiny-mole [99]

$\cos^2\theta=1-\sin^2\theta$

$2\cos^2\theta=\sin\theta+1$
$2-2\sin^2\theta=\sin\theta+1$
$2\sin^2\theta+\sin\theta-1=0$
$(2\sin\theta-1)(\sin\theta+1)=0$

$2\sin\theta-1=0\implies \sin\theta=\dfrac12\implies\theta=\dfrac\pi6,\dfrac{5\pi}6$
$\sin\theta+1=0\implies\sin\theta=-1\implies\theta=\dfrac{3\pi}2$

7 0

3 years ago

?? “solve the missing elements for each problem. use 3.14 for area

velikii [3]

Answer:

Problem 4:

Radius = 11 cm.

Circumference = 69.08 cm.

Problem 5:

Radius = 14 mm.

Circumference = 87.92 mm.

Problem 6:

Radius = 9 inches.

Circumference = 56.52 inches.

Problem 7:

Diameter = 32 ft.

Circumference = 100.48 ft.

Problem 8:

Diameter = 26 yards.

Circumference = 81.64 yards.

Problem 9:

Diameter = 12 cm.

Circumference = 37.68 cm.

Step-by-step explanation:

Problem 4:

Given:

Diameter GH = 22 cm

We need to find the radius EF and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius EF = $\frac{1}{2}\times Diameter = \frac{1}{2}\times 22 = 11 \ cm$

Circumference = $\pi \times Diameter = 3.14 \times 22 = 69.08\ cm$

Hence Radius = 11 cm

Circumference = 69.08 cm.

Problem 5:

Given:

Diameter OP = 28 mm

We need to find the radius MN and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius MN = $\frac{1}{2}\times Diameter = \frac{1}{2}\times 28 = 14 \ mm$

Circumference = $\pi \times Diameter = 3.14 \times 28 = 87.92\ mm$

Hence Radius = 14 mm

Circumference = 87.92 mm.

Problem 6:

Given:

Diameter EF = 18 inches

We need to find the radius CD and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius CD = $\frac{1}{2}\times Diameter = \frac{1}{2}\times 18 = 9 \ in$

Circumference = $\pi \times Diameter = 3.14 \times 18 = 56.52\ in$

Hence Radius = 9 inches.

Circumference = 56.52 inches.

Problem 7:

Given:

Radius GH = 16 ft

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter KJ = $2 \times radius = 2 \times 16 = 32 \ ft$

Circumference = $\pi \times Diameter = 3.14 \times 32 = 100.48\ ft$

Hence Diameter = 32 ft.

Circumference = 100.48 ft.

Problem 8:

Given:

Radius LM = 13 yards

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter NO = $2 \times radius = 2 \times 13 = 26 \ yards$

Circumference = $\pi \times Diameter = 3.14 \times 26 = 81.64\ yards$

Hence Diameter = 26 yards.

Circumference = 81.64 yards.

Problem 9:

Given:

Radius NO = 6 cm

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter PQ = $2 \times radius = 2 \times 6 = 12 \ cm$

Circumference = $\pi \times Diameter = 3.14 \times 12 = 37.68\ cm$

Hence Diameter = 12 cm.

Circumference = 37.68 cm.

3 0

3 years ago

The radius of a circle is 17m. find its area in terms of pi

frozen [14]

Answer:

Step-by-step explanation:

Given, 

Radius of a circle = 17m

Therefore, 

Area in terms of pi

$= \pi {r}^{2}$

$= \pi \times 17m \times 17m$

$= 289\pi {m}^{2} (ans)$

5 0

3 years ago

Read 2 more answers

Am I doing this right?

Lubov Fominskaja [6]

GCF(16, 14) = 2 Note: 14 is not divisible by 4.
GCF(24, 32) = 8 because
24 = 2 x 2 x 2 x 3
32 = 2 x 2 x 2 x 2 x 2 GCF = 2 x 2 x 2 = 8
GCF(10w, 5w) = 5w because the w is a common factor, too.
GCF(16xy, 24xy) = 8xy because x and y are factors common to both
GCF(21ab, 35a) = 7a because a is a common factor, but b is not
GCF(10jk, 15k) = 5k
GCF(3mn, 9mn, 12mn) = 3mn

6 0

4 years ago

Hugo is writing a coordinate proof to show that the midpoints of a quadrilateral are the vertices of a parallelogram. He starts

lesantik [10]

Answer: Heres the answers!

8 0

4 years ago