Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
; 

60% - 3/5
Hope this help, don't really know what your expecting the answer to be
9514 1404 393
Answer:
Step-by-step explanation:
There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.
Let m = 0i +1j +ak. Then we require ...
m·p = 0 = 0×1 +1×2 +a(-2) ⇒ 0 = 2 -2a ⇒ a = 1
m = 0i +1j +1k
__
Let n = 2i +0j +bk
n·p = 0 = 2×1 +0×2 +b(-2) ⇒ 2 -2b = 0 ⇒ b = 1
n = 2i +0j +1k
Answer:
11:00 am< 6
84>6
Step-by-step explanation: