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kolbaska11 [484]
3 years ago
5

Help please, giving BRAINLIEST!!!

Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0
10 have a good day byeeee
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Calculate the value of the expression <br> 1, 284°
ladessa [460]
It would be 1,284° couculated by absolute rubies
5 0
3 years ago
Graph the linear equation. find three points that solve the equation x+y=-2
vagabundo [1.1K]

Answer:

See the graph of the given linear equation shown below.

Explanation:

Given the linear equation : x+y = -2

We make a table for values of x and y;

x               y = -2-x

0               -2

-2               0

1                -3

Now, plot these three points (0, -2) , (-2, 0) and (1, -3) on the coordinate plane.

You can see the graph as shown below.


6 0
4 years ago
A triangle can be formed with side lengths 2 in, 3 in, and 6 in.
evablogger [386]
The two small sides of the triangle should add up and equal to the largest side.
2 + 3 = 5, 5 is smaller than 6, so the answer is NO because, at least there is a side that has the number close to each other, but if it is too far away, then 2 in can't reach to 6 in. to formed a triangle
So the answer is No
Hoped this will helped you!
If you don't believe me, draw the triangle on your paper and you'll see:)
4 0
4 years ago
Read 2 more answers
77. Find the greatest common factor (GCF) of the polynomial: 12x^4 + 8x^3 - 16x^2
Fed [463]

Answer:

4x^2

Step-by-step explanation:

The greatest common factor of 12, 8, and 16 can be no larger than the smallest difference between these numbers, which is 4. 4 is a factor of each number, so is the GCF of them.

The exponent of the greatest common factor of x^4, x^3, and x^2 can be no larger than the smallest of these exponents, which is 2. So, the GCF of the variable portion of the terms is x^2.

The product of the coefficient GCF and the variable GCF is ...

... 4x^2

5 0
3 years ago
*BRAINLIEST* (EASY QA: Warm UP) Find a positive solution to each equation: x2 = 1/4
Georgia [21]

\qquad\qquad\huge\underline{{\sf Answer}}

\textbf{Let's get it solved :}

  • \sf{x² = \dfrac{1}{4}}

  • \sf{x = \sqrt{\dfrac{1}{4}}}

  • \sf{x= \pm{\dfrac{1}{2}}}

  • \sf{x ={\dfrac{1}{2}} }

\textsf{[ since we need positive solution ]}

\textsf{Correct choice is C}

4 0
3 years ago
Read 2 more answers
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