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gavmur [86]
2 years ago
5

What is 50.00 simplified

Mathematics
1 answer:
stira [4]2 years ago
3 0

Answer:

50

Step-by-step explanation:

cause you just take away the decimals and its alreasy a whole number

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Lana has $15 for dinner her meal is $13.90 she wants to leave a 18% tip does she have enough explain your answer
denis-greek [22]

Start off by finding 18% of 13.90.

18%=18/100=0.18

0.18(13.9)=2.5

An 18% tip would be $2.50.


Now, to find out if Lana has enough money, add $2.50 to $13.90 to find out the total amount she would leave.  You get $16.40.  Since $16.40>$15, the answer is no because the total cost including the 18% tip is greater than $15.

3 0
3 years ago
What is the value of 6 in 70,681? Explain how you know.
Dafna11 [192]

Answer:

it's 100

Step-by-step explanation:

70000

0000

600

80

1

I don't know if you understand

6 0
2 years ago
The angles in a triangle are in the ratio 2 : 3:7.
Mademuasel [1]

Answer:

30°, 45° and 105°

Step-by-step explanation:

2 + 3 + 7 = 12 parts

180/12 = 15 degrees each part

First angle (2 parts)

2(15) = 30°

Second angle (3 parts)

3(15) = 45°

Third angle (7 parts)

7(15) = 105°

Hope this helps

3 0
1 year ago
Is sin theta=5/6, what are the values of cos theta and tan theta?
mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

5 0
3 years ago
Help me with this problem please
Ymorist [56]

Answer:

-15

Step-by-step explanation:

3^2 - 3 x [(5^2 - 9) / 2 ]

9 - 3 x [(25 - 9) / 2]

9 - 3 x (16/2)

9 - 3 x 8

9 - 24

-15

5 0
3 years ago
Read 2 more answers
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